Re: Is there Time Dilation if Twins circle the Earth at 1/3c??
From: Androcles (Androcles_at_)
Date: 02/12/05
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Date: Sat, 12 Feb 2005 04:10:52 GMT
<alanmc95210@yahoo.com> wrote in message
news:1108176670.323788.32600@z14g2000cwz.googlegroups.com...
> g...@hotmail.com Feb 11, 11:14 am show options
>
> Strange Phenomena question?
>
>
> 1. Question:
>
>
> The further the twin distances himself in a straight line from Earth
> (1/3c) then just as the twin turns around (-1/3c), if the Earth then
> also travels at 1/3c to meet him *HALF-WAY* then both their clocks
> will
>
> be the same again? Correct?
>
> ***
> Nope, the first twin will age slower while traveling away at 1/3 c,
> then both the earth and the traveller will age slower at the same
> rate as they come together at a speed they (earth and traveller)
> measure as (1/3 + 1/3)/( 1 + 1/9) the speed of light. I'm assuming
> that 1/3 speed is measured from the point of view of a Martian, which
> is pretty nearly at rest compared to the Earth. If a rest frame is
> not
> specified, that part about earth also travelling at 1/3 c doesn't make
> good sense. Try reading a book about relativity- Martin Gardner's book
> is easily understood- A. McIntire#
LOL!
If at the points A and B of K there are stationary clocks which, viewed
in the stationary system, are synchronous; and if the clock at A is
moved with the velocity v along the line AB to B, then on its arrival at
B the two clocks no longer synchronize, but the clock moved from A to B
lags behind the other which has remained at B by (1/2) tv^/c^2(up to
magnitudes of fourth and higher order), t being the time occupied in the
journey from A to B.
It is at once apparent that this result still holds good if the clock
moves from A to B in any polygonal line, and also when the points A and
B coincide.
If we assume that the result proved for a polygonal line is also valid
for a continuously curved line, we arrive at this result: If one of two
synchronous clocks at A is moved in a closed curve with constant
velocity until it returns to A, the journey lasting t seconds, then by
the clock which has remained at rest the travelled clock on its arrival
at A will be (1/2) tv^/c^2 second slow.
Einstein's paper is easily understood, but not by total cretins.
Androcles.
>
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