Re: Two photons... relative distance question

Note that the two frames are aligned on photon A so that photon A's
position = Ax = Ax' = 0;
and they are aligned with respect to time so that t = t' = 0.
I think that the answer is as follows, where Bx' = photon B's position
in Frame 1 and Bx = photon B's position in Frame 2:

Bx = gamma Bx' + gamma v t'
= gamma 449688687m + gamma 0.5c 0
= gamma 449688687m
= 1 / sqrt(1 - v squared/c squared) * 449688687m
= 1 / sqrt(1 - 0.5c squared/c squard) * 449688687m
= 1 / sqrt(1 - 0.25) * 449688687m
= 1 / sqrt(0.75) * 449688687m
= 1 / 0.86602540378443864676372317075294 * 449688687m
= 1.1547005383792515290182975610039 * 449688687m
= 519255768.9819587m

Is that right?

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