Re: relativity of simultaneity - real or perceived?
- From: "Curious" <anthonyroseuk-curious@xxxxxxxxxxx>
- Date: 14 May 2005 17:01:47 -0700
Jon, I am very surprised to see your diagram! Thanks very much - it
makes the figures very much clearer. This confirms my understanding of
what you are saying.
However, this is not where my curiousity lies.
I need to know whether the equations are telling us where the particles
would be *perceived* to be to an observer at x' = 0 and t' = 0, or
whether they are telling us where the particle actually is wrt to frame
2. If for example we were on a spaceship travelling at 0.5c some time
before this event, and had to be able to calculate exactly where the
two particles would be at time t' = 0 given that we know where they
will be wrt frame 1 at time t = 0, would we expect particle B to be at
x' = 0.87 and the right end of the box at x' = 1.3?
Is this saying that for frame of reference 2, the two particles do NOT
pass each end of the box simultaneously - in other words, is this
saying that two contradictory scenarios both occur?
Would you agree with Paul that they are EITHER simultaneous events OR
not? Or do you go for the 'there is no absolute reality, we can only
know what we measure' view shared by Dave A. Smith, and believe that
they are both simultaneous AND non-simultaneous?
Or do you say that this is where the evidence leads, despite that fact
that it is beyond us to understand the multiple 'realities'?
If the box was a bomb that blew up instantly when two photons hit it
simultaneously at both ends, would an observer in frame 1 see it
explode but an observer in frame 2 see it remain unexploded?
.
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