Re: why people pretend that the moon landing was for real




"Paul B. Andersen" <paul.b.andersen@xxxxxxxxxxxxxxxx> wrote in message
news:d6qm7f$etq$1@xxxxxxxxxxxxxxxxxxx
>
> The power radiated from a body with temperature T is:
> Pe = E*sigma*A*T^4
> where:
> E is the emissivity
> sigma = 5.67*10^-8 W/(m^2*K^4)
> A is the surface area of the body.
>
> The power absorbed by a body 1AU from the Sun is:
> Pa = E*So*Ac
> where
> E is the emissivity
> So is the solar constant = 1.37*10^3 W/m^2
> Ac is the area of the cross section of the body
> perpendicular to the direction to the Sun
>
> The body will be in thermal equilibrium when Pe = Pa
> E*sigma*A*T^4 = E*So*Ac
> T^4 = (So/sigma)*Ac/A = 2.42*10^10*Ac/A K^4
>
> The ratio Ac/A depend on the shape and orientation of the body.
>
> For a sphere Ac/A = 0.25
> T = 279K or 6 deg C. Chilly, but not freezing.
>
> For a cube Ac/A = 1/6 = 0.167
> T = 252K or -21 C. Freezing!
>
> For a cylinder with length 4 radii:
> Ac/A = ca. 0.25 if its length axis is perpendicular to the Sun.
> T = 279K or 6 C.
> Ac/A = 0.1 if its length axis points to the Sun.
> T = 222K, or -51 C. Freezing indeed!!
>
> So what temperature Apollo 13 would approach depend
> on its exact shape and orientation. But it would
> most probably be below zero degree C.

Excellent post. Thanks for correcting me. I had no idea thermal radiation
could be that high. I thought it was only limited by black body radiation.

The following is from the other post.

"Paul B. Andersen" <paul.b.andersen@xxxxxxxxxxxxxxxx> wrote in message
news:d6qmc8$etq$2@xxxxxxxxxxxxxxxxxxx
>
> 1. The Apollo mission is a hoax because the radiation in and beyond
> the Van Allen belts is so high that the astronaughts would have died.

Do you have a better explanation? I don't.

> 2. The high radiation in the Van Allen belts is a hoax made by
> the manufacturers of communication satellites.

No, communication satellites operate beyond the Van Allen Belts in the
geosynchronous orbit. The article I presented has not referenced to Van
Allen Belts as a
consideration of radiation source. Got any better ideas?

> Have I got your point?
> Is it "everything is a hoax"?

Not necessarily.





.



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