Re: Bending of light not well authenticated


"Gene McGraw" <emcgraw@xxxxxxxxxx> wrote in message
news:42917d84.47908468@xxxxxxxxxxxxxxx
>
> As stated above, R is the radial coordinate of the
> light path at the perihelion (the point of closest approach to the
> gravitating mass M).

You are not making any sense. If R is the radius of the sun, it cannot be
the perihelion. In order for a photon to bend in observed spacetime
affected by the Schwarzschild metric, it must be deflected a distance into
the sun at its perihelion. You cannot use the condition of the proper
spacetime where there is no distortion taken place to apply it to the
observed spacetime.

>>See. Your understanding of GR is not complete. In every spacetime
>>equation, there are always...
>
> It's quite obvious that you know nothing at all about general
> relativity, so there's really no point in you pretending to instruct
> anyone in that subject. The question is, do you want to learn how
> general relativity predicts the deflection of light, or don't you?

You have not understood the concept of proper spacetime, and this is not
unique to GR.

>>What I have been trying to tell you is that your concept is wrong because
>>if the mass of the sun were to be any larger, the photon cannot escape
>>from the sun. There would be no deflection because the photon is
>>captured by the sun.
>
> Stop and think for just one minute. The distant star is sending out
> rays of light in all directions, passing at all distances from the
> Sun, some close, some far. If the mass of the Sun was suddenly
> increased, the ray that had previously just grazed the Sun would now
> slam into the sun, BUT... a ray that previously passed further from
> the Sun would now be pulled in so it now just grazed the sun, and
> that's the ray we would see. No matter how massive the Sun is, as we
> look at the distant star in the sky, with the Sun getting closer and
> closer, there will be a point when the star is just visible at the
> edge of the Sun. And at that moment the path of light has a perihelion
> distance of R, and it has a certain amount of deflection, and that's
> what I showed you how to determine from the field equations of general
> relativity. You're welcome.

Schwarzschild metric predicts black holes. What you are saying contradicts
with Schwarschild metric. Again, the perihelion must be a function of the
curvature of spacetime. And again, this is not unique to GR. So, stop BS
your way behind the weight of GR.

>>You are totally lost... Maybe after you have understood what I am talking
>>about we can continue with our discussion.
>
> I understand exactly what you're talking about. That's how I know
> you're an ignorant self-deluded moron.

If you do understand what I am saying, then your intention must be of
sinister in nature.


.

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