Re: Electo London Gravity ?


"sue jahn" <susysewnshow@xxxxxxxxxxxx> wrote in message
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|
| "Significant Zero" <paulpsremove@xxxxxxxxxx> wrote in message
news:1120898491.23195.0@xxxxxxxxxxxxxxxxxxxx
| >
| > "sue jahn" <susysewnshow@xxxxxxxxxxxx> wrote in message
| > news:42ce9741$0$18636$14726298@xxxxxxxxxxxxxxxxxx
| > |
| > | "Significant Zero" <paulpsremove@xxxxxxxxxx> wrote in message
| > news:1120833200.30126.0@xxxxxxxxxxxxxxxxxxxxx
| > | >
| > | > "sue jahn" <susysewnshow@xxxxxxxxxxxx> wrote in message
| > | > news:42cb8a9d$0$18640$14726298@xxxxxxxxxxxxxxxxxx
| > | > |
| > | > | "sue jahn" <susysewnshow@xxxxxxxxxxxx> wrote in message
| > | > news:42b9c325$0$18649$14726298@xxxxxxxxxxxxxxxxxx
| > snip
| > | To your point. We should have no ambiguity with the far-field effects.
| > | Might we clear up the matter with the statements?::
| > | Gravitational force diminishes by 1/r^2 above the earths surface.
| > | Gravitational force diminishes by 1/r^1 below the earths surface.
| >
| > I thought that below the surface it fell to zero at the center of the
| > partical at the center of the earth but still followed a 1/r^2 as far as
the
| > feet of a person in a lift was concerned ?
|
| That is what I get for trying to speak a foreign language.
|
| Graviational force is maximum at the earth's surface because
| 100% of it's mass is concentrated below your toes..
|
| Gravitational force is zero at the earth's center because any
| plane cut through a test mass has 50% of the earths mass
| on either side.
|
| Force is directly proportional to the distance from center.
| Is 1/r or 1/r^1 the way to say that ? My spelling is much better
| than my math. :o)

It is claimed at http://hyperphysics.phy-astr.gsu.edu/hbase/forces/isq.html
that Gravity source strength equals 4 pi GM = I_s and the surface intensity
is 4 pi GM/4 pi r^2 so 4 pi GM/4 pi r^2 = I_e = GM/r^2 = g so g = 9.80665 m
s ^-2 = I_e at r_e which I hope means the same as m s-2 with ^ meaning a
superscript exponent to you and others and in long hand meters per second
per second ? So twice the center to surface radius from the center is 2r_e
and the intensity there is I_2r_e = g_e/4 and three times the center to
surface radius is 3r_e so at 3r_e we have I_3r_e = g_e/9

So the gravitational field intensity at
0r = GM ?
1/2r = GM/1/2r^2 ?
1r = g = 9.80665 ms^-2 = GM/r^2
2r = GM/2r^2 = 2.4516625 m s^-2
3r = GM/3r^2 = 1.0896277 m s ^-2

So 1/r^2 seems a good ? approximate for above the surface ? Mind you the
atmosphere may alter the 1/r^2 slope of the field slightly above the surface
and seems to fit in nicely with Electric field slopes, Electric field
propagation dispersion in the far field and Coulomb at 1/d^2. Have not had
chance to look up details yet but could near field be fitted into r0 to r1
as far as gravity, E-fields goes ? I still have not been able to fit 1/r^1
in as that just seems to state it is what it is. ? Sorry about no jokes at
the moment still a bit pissed off. {:-(

|
| Above the earth's surface, the force diminishes by 1/r^2.
| You can not increase the concentration of mass below your
| toes greater than 100% by moving farther from the center
| after you pass the surface and head toward outer space.
|
| >
| > |
| > | and from the source document:
| > | <<As the non-bonded interaction between atoms and groups
| > | involves less than full formal charge and involves polarization
| > | contributions, the distance dependence falls of more quickly
| > | than the 1/r dependence of Coulomb's law.
| >
| > Coulomb's law has a 1/d^2 dependence and an electric field has 1/r^2
| > dependence AFAIK so where is the 1/r dependence coming from ?
|
| Let's sort this out with the planet earth first. Questions above.
|
|
| >
| >
| > | In these more
| > | complicated cases, where the charges can not be represented
| > | by single point locations, the interactions are also less isotropic,
| > | falling off not just as a function of distance, but also as a
| > | function of orientation: >>
| > |
| > | As the source document involves forces *within* some kind
| > | of fluid or solid, a polymer scientist probaby has little need
| > | for the far-field situation. 1/r^2.
| > |
| > |
| > | Sue...
| > | Pardon my careless interchange of d distance and r radius.
| >
| > I thought it made no difference unless you were inside the the point
source.
|
| In some cases we are.
|
| Eh! If I knew the Chineese symbol for it I would toss that in
| too just ta keep ya on yer toes. :o)
|
| Sue...
|
| > ?
| >
| > |
| > | > --
| > | > Significant Zero E-field = Electric field, M-field =Magnetic
field,
| > two
| > | > unbound field effects
| > | > http://home.freeuk.com/paulps/
| > | > Maybe updates. The spuds, beans and onions are coming up nicely.
Ooh
| > | > ah.{:-)
| > | >
| > | >
| > | > | ----
| > | > | Sue...
| > | > |
| > | > |
| > | >
| > | >
| > |
| > |
| >
| >
|
|


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