Re: Question about light clock and derivation of time dilation
- From: "Androcles" <Androcles@ MyPlace.org>
- Date: Sun, 10 Jul 2005 17:46:34 GMT
"Daryl McCullough" <stevendaryl3016@xxxxxxxxx> wrote in message
news:dargis0a86@xxxxxxxxxxxxxxxxxx
> Androcles says...
>
>>Look.
>>We can return to the moon, but not to Neil Armstrong planting a
>>footprint in 1979.
>
> So what? The fact that there is a vector with components
>
> x=0
> y=0
> z=0
> t=-26
The FACT that there ISN'T any such vector except in your mind
means you CAN'T go to any event it describes, but you CAN go to
x = -1
y = 0,
z = 0
t = 2.
Or you can go to
x = 0
y = 0
z = 0
t = 2006
without moving a muscle.
Stay right where you are, 2006 WILL come to you.
> doesn't imply that we can *move* in that direction. The laws
> of physics determine which vectors are possible displacement
> vectors for a physical object, and not all of them are.
The laws of a vector space determine that time is not a vector,
it has no inverse.
Physics has mathematical laws.
Relativity isn't physics, it is gobbledygook, a thought experiment,
a gedanken, a figment of your imagination, and it has its own set of
self-contradictory rules for the quasi-world in which you and other
crazy people live in.
>
> For a material object of nonzero mass, it is only possible
> to go from event A with coordinates x_A, y_A, z_A, t_A to
> event B with coordinates x_B, y_B, z_B, t_B if
>
> (1) t_A < t_B
That's it. Well done.
(x1,y1,z1, B) cannot be subtracted from (x2,y2,z2, A), it's an illegal
operation.
Time is not a vector, t_A < t_B.
> (2) (x_B - x_A)^2 + (y_B - y_A)^2 + (z_B - z_A)^2 < c^2 (t_B -
> t_A)^2
>
>>Let (x1,y1,z1,t1) be a 4-vector.
>>Let (x2,y2,z2,t2) be a 4-vector.
>>
>>Add the vectors.
>>(x1-x2, y1-y2, z1-z2, t1-t2)
>>
>>Put in numbers
>>x1 = y1 = z1 = t1 = 1
>>x2 = y2 = z2 = t2 = -1
>>(1-1,1-1,1-1, 1-1) = (0,0,0,0)
>>
>>I've now moved from (1,1,1, 1pm)
>>to (0,0,0, midday) and gone backwards in time.
>
> No, you haven't.
Of course I haven't, there is no t = -1.
>
> The fact that I can construct a vector from
> here to Alpha Centauri doesn't mean that I've
> travelled to Alpha Centauri.
Of course you can, only time and money prevent it.
Mathematics doesn't.
> You seem to be confused about the difference
> between adding vectors and travelling through
> spacetime. You'll never get to Alpha Centauri
> by adding vectors.
I'd like to see you raise your hand WITHOUT adding vectors.
Androcles.
.
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