About GR (kst)
- From: "Ken S. Tucker" <dynamics@xxxxxxxxxxxx>
- Date: 21 Jul 2005 23:54:49 -0700
You and I are astronauts, sitting on the pad
and the count-down begins, 5,4,3,2,1...blast-off!
at t=1.
The g-meter goes from 1g to 2,3,4,5g and stabilizes.
A mechanical deformation heated the space-craft
as it strained under the effects of the acceleration,
the space-craft was heated and an extra infared
energy was produced and emitted.
You look out the window and find you're still
sitting on the pad......why?
Answer:
At t=1 the Earth's density increased by factors,
1,2,3,4,5, hence it's mass increased likewise
while the volume and radius remained constant.
Using AE's law G_uv=k*T_uv we would find,
Guv at (t=5) = 5*Guv at (t=1) and
Tuv at (t=5) = 5* Tuv at (t=1).
The later is interesting, because as the acceleration
increased, the space-craft was heated and emitted
quantized radiation in the infared spectrum.
The change in Guv from t=1 to t=5 appeared to the
astronaut's to be acceleration, but in fact, it was a
gravitational change given by,
g00-1 (at t=5) = 5*(g00-1) (at t=1),
as the Earth's density increased.
That's AE's law G_uv =k*T_uv in operation with the
Principle of Equivalence.
Normally GRist's use G_uv=0 and Schwart's Solution,
but in juxtaposition this example demo's the induction
of heat when a change in T_uv occurs and creates
quantum radiation using the differential of the realistic
G_uv =k*T_uv.
The induction needs the relative motion of charges,
therefore the AE law applies to a relation.
((the continuum is being replaced by relations))
That differential that outputs the infared radiation is
discontinuous, aka quantized, hence,
T_uv;w =0 ,however,
T_uv;w is not a constant.
but the integral
$ T_uv;w dx^w = a relative constant .
Physically, we're incrementing the energy in
a volume of spacetime by inducing a quanta
of energy like a photon, or perhaps emitting,
as the spacecraft is deformed, and from various
refs, that constant is relativistic.
Ken S. Tucker
.
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