Re: Helical Particle Waves.


<vanep@xxxxxxx> wrote in message
news:1122493611.173620.192150@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
>
>
> Len Gaasenbeek wrote:
> > Subject: Helical Particle waves.
> > See: http://www2.rideau.net/gaasbeek 'Selected Papers', Helical
Particle
> > Waves, formula [3].
> >
> >
> > > Hello Sir,
> > >
> > > I really beleive that the mechanism governing EM waves is quite close
to
> > the
> > > helical model you suggest. It surely makes more sense than what is
> > currently
> > > the accepted model.
> > >
> > > However I do have problems understanding how you arrived at the
relation
> > shown
> > > here:
> > >
> > > http://www2.rideau.net/gaasbeek/f1_3.gif
> > >
> > > I would be very pleased if you can clarify this equation for me.
> > >
> > > Thanks in advance
> > > -------
> > >
> > ...........................................................
> > To -------,
> >
> > In answer to your question above, I concluded that the kinetic energy of
a
> > relativistic particle which is accelerated closer and closer to the
speed of
> > light c continues to increase, not because its 'relativistic mass'
increases
> > but because it continues to increase its speed by increasing its
peripheral
> > speed.
> >
> > That is to say, even though the helical wave particle can't travel or
> > progress through space at a speed greater than c, its helical speed can
> > increase to a speed greater than c as it is a combination of its linear
AND
> > peripheral speed. Of course its helical wave VELOCITY continuously
changes,
> > since it continues to change DIRECTION as it follows its helical
trajectory.
> > However the kinetic energy of the relativistic particle is a function of
its
> > speed, regardless of its direction, since k = 1/2 m v^2.
> >
> > Now we know that the kinetic energy of the helical wave particle
approaches
> > infinity as its linear velocity approaches c. Since its linear speed is
> > limited to c this means that its peripheral speed must become infinitely
> > large for its helical speed to become infinite. This means that for
> > practical purposes its helical speed approaches its peripheral speed
when
> > its linear speed approaches c, since the peripheral speed contributes
the
> > lion share to its kinetic energy.
> >
> > Or as v(linear) approaches c, v(helical) approaches v(peripheral).
> > Or, v(linear) / c = v(peripheral) / v(helical) [3]
> >
> > Now the above tends to hold for long helical waves of low frequency.
> > In reality the most energetic helical wave particles tend to be of high
> > frequency and short wave-length and amplitude. So how do these
particles
> > continue to gain kinetic energy as they are accelerated, since their
> > peripheral speed tends to approach zero?
> >
> > The explanation is that all helical wave particles spin around their own
> > axis as they travel along.
> > Long wave, low frequency helical wave particles spin relatively slowly
> > around their axis.
> > Short wave, high frequency helical wave particles spin rapidly around
their
> > own axis.
> >
> > Since the spin of a particle contributes to its kinetic energy, in the
case
> > of a high frequency
> > helical wave particle, its spin contributes most to its kinetic energy
> > rather than its nearly none existent peripheral speed.
> >
> > By the way, the sideways gyroscopic force the relativistic helical wave
> > particle exerts on itself is a function of the rate at which it spins
around
> > its own axis and the rate at which its axis gyrates (the two are
> > inter-related since the latter is equal to its helical wave frequency)
as it
> > travels along. Consequently, the higher the spin of a relativistic
> > particle, the smaller its amplitude and peripheral speed.
> >
> > See formula [6].
> >
> > Enjoy, Len.
> > ............................................................
>
>
> The increase in system energy is the result, and equal to, the energy
> added to the system during acceleration. The energy equation works
> nicely and we get the added benefit of not having to deal with reems of
> 'convoluted hogwash' to describe what is happening.
>
> James
......................................................
To James,

Thanks!

Len.
....................................................


.

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