Re: Gravity


"Significant Zero" <paulpsremove@xxxxxxxxxx> wrote in message
news:1123400169.6216.0@xxxxxxxxxxxxxxxxxxxxx
>
> "Bill Hobba" <rubbish@xxxxxxxx> wrote in message
> news:sUaJe.73646$oJ.60649@xxxxxxxxxxxxxxxxxxxxxxxxxxxxx
> |
> | "Significant Zero" <paulpsremove@xxxxxxxxxx> wrote in message
> | news:1123318261.18931.1@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
> | >
> | > "Bill Hobba" <rubbish@xxxxxxxx> wrote in message
> | > news:%pTIe.72831$oJ.29812@xxxxxxxxxxxxxxxxxxxxxxxxxxxxx
> | > |
> | > | "PD" <TheDraperFamily@xxxxxxxxx> wrote in message
> | > | news:1123255006.164364.289640@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
> | > | > Would you like roquefort or thousand island dressing with that
> | > | > character salad?
> | > |
> | > | I thought about responding but could not make out what it was
> getting
> | > at.
> | > | Glad someone else agrees.
> | > |
> | > | Thanks
> | > | Bill
> | > |
> | > | >
> | > | > PD
> | > | >
> | >
> | > That because it was not trying to get *at* anything Bill
> |
> | How true, how very true.
> |
> | > it is just an
> | > attempt to clarify a state of confusion, on who's part it remains to
> be
> | > seen.
> |
> | It is quite obvious who is confused and despite many invitations to
> correct
> | that confusion refuses to.
> |
> | Bill
>
> When you are able to clearly answer the hard questions without avoidance
> and
> not hid behind a lorry load of clichés, misdirection, just no constructive
> replys and when you have run out of these methods then resorting to
> disparaging personal attacks you might have more success {:-)

Let us see how the dialogue with you goes. Write gibberish that a number of
people recognize as gibberish then when it is pointed out it is gibberish
(and people try and help you understand the basics so you can at least
present you ideas coherently) claim people are avoiding the hard questions.
As another regular poster says - plonk.

Bill

>
> |
> | >
> | > --
> | > Significant Zero E-field = Electric field, M-field =Magnetic field,
> two
> | > unbound field effects
> | > http://home.freeuk.com/paulps/
> | > Maybe updates. (1-(1/(1/3))^2)/(1 + (1/(1/3))^2) = - 0.08 = FTL
> ? -p<+p
> | > or
> | > (m*-v)<(m*+v) or (m*-c^2)<(m*+c^2) =g?
> | >
> | >
> |
> |
>
>


.

Relevant Pages

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  • Re: Gravity
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    (sci.physics.relativity)