Re: Is temperature relative?

Dear sal:

"sal" <pragmatist@xxxxxxxxxx> wrote in message
news:pan.2005.08.23.14.48.02.494423@xxxxxxxxxxxxx
> Re-read your post, decided I should post a more appropriate
> response.
>
> See also <pan.2005.08.23.14.35.56.575676@xxxxxxxxxx>
>
> On Sat, 20 Aug 2005 08:00:08 -0700, N:dlzc D:aol T:com (dlzc)
> wrote:
....
>>> 1/sqrt(1-v^2) -- rather standard, actually.
>>
>> Put a value inclusive of 0, not inclusive of 1, for v. What
>> value do you get for g? Now look at how you are
>> applying this factor between moving and stationary
>> frames. This is a first-grader error you are making, to
>> confuse yourself. The domain of g is 1 <= g < oo.
>
> I re-read this a few days later and I still don't see what
> you're trying to get at.
>
> If you were trying to say the E field should, in this
> particular case, transform as
>
> E' = E/g
>
> not as
>
> E = E'/g
>
> because you need to transform from the moving frame
> to the lab frame, why didn't you just say so?
>
> And if that's not what you were trying to say, then what
> was the point you were making?

Let me make this point instead...
"Fools step in where angels fear to tread."
I was not qualified to be of any real help. It was the details
you needed help with, and the details I couldn't help with. I
apologize for attempting what I could not do, and confusing you
in the process.

David A. Smith


.

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