Re: Rigid rod problem

Kim B wrote:

[snip]

> If you choose a point on the rod a use its current speed as your FOR,
> the the rest of the rod will fit nicely in this FOR (along the FOR's
> line of simultaneity) ... with the same speed all along and the
> correct proper length, exactly as it fits in our "rest" frame at the
> base line ... all frames are equal, assuming the rod has accelerated
> and will accelerate forever.

Thanks. Of course you are quite right about that, and I
apologize for my many mistakes here.

.

Relevant Pages

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