absolute time and the etheristic SR Doppler

The most intuitive concept about time is the absolute time: in this instant
something is going on in every place in the universe, as it could be seen if
we had the light travelling at infinite speed.

We can use this concept to analize the classic Doppler and the SR Doppler:

a absolutely moving source (at .5 C) that is emitting for a unit of absolute
time. This duration of time is Doppler shifted to 1-Vs in the direction of
the movement of the source.

If there is an approaching absolutely moving mirror (at .4 C) the time of
the duration of the receved light by the mirror is Tf=(1-Vs)/(1+Vm): one way
forth Doppler source-mirror:

Tf=.5/1.4=0.357142857

If the mirror was to reflect a light pulse lasting a unit of absolute time
this time would be shifted to 1-Vm and received by the source as
Tb=(1-Vm)/(1+Vs): one way back Doppler mirror-source:

Tb=.6/1.5=.4


The forth and back doppler is Tf*Tb=(1-Vs)/(1+Vm)*(1-Vm)/(1+Vs)=
Tf*Tb=0.357142857*.4=0.142857142857=1/7

The two ways Doppler shifted time of the signal is Tr=1/7*To

Now a relativis may consider the source stationary and the mirror moving, in
order to have a Two Way Doppler shifted time of 1/7 you must have a
approaching mirror at a speed of .75 C:

Two ways = To*(1-Vm)/(1+Vm)= .25/1.75= 0.142857142857= 1/7

Since the relativist consider the one way forth identical to one way back:
one way=sqroot(.25/1.75)=0.37796447

Summary:

ether classical Doppler:
one way forth = 0.357142857
one way back = .4
Two ways = 1/7
note: The closing speed of Vs+Vm=.9 C cannot be used to calculate the
Doppler

SR Doppler:
one way forth = 0.37796447
one way Back = 0.37796447
two ways = 1/7
Relative speed=(vS+Vm)/(1+(vS*Vm))=(.5+.4)/(1+(.5*.4))=.75 C

*****
The classic etheristic SR:

SR Doppler forth:
one unit of the source local time = 1/sqr(1-Vs^2)=1.1547005
is received by the mirror as
(absolute unit source local time)* (one way Doppler etheristic forth)*(time
rate mirror clock)=

=1.1547005 * 0.357142857 * 0,916515138 =Doppler forth= 0,37796447 as SR
predict.

Absolute time received by the mirror =1.1547005 * 0.357142857 =0,412393035

SR Doppler back:
one unit of the mirror local time = 1/sqr(1-Vm^2)=1,0910894511799
is received by the source as

(absolute unit mirror local time) * (one way Doppler etheristic back) *
(time rate source clock)=

1,0910894511799 * .4 * 0,866025403 = Doppler back= 0,37796447 as SR
predict and identical to SR Doppler forth

Absolute time received by the source= 1,0910894511799 * .4 = 0,6910894511799

as you can see the SR one ways Doppler are identical but
the absolute time received by the mirror and by the source are different and
would be different for each possible couple having the same relative speed
of .75 C.

With the hidden absolute times and with the ether, the physical analisys of
Doppler is complete.

best regards

beda pietanza



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