Re: OWLS & Out of Sync Clocks-By How Much Are They Out of Sync.
- From: The Ghost In The Machine <ewill@xxxxxxxxxxxxxxxxxxxxxxx>
- Date: Sat, 05 Nov 2005 06:00:09 GMT
In sci.physics.relativity, kenseto@xxxxxxxxxx
<kenseto@xxxxxxxxxx>
wrote
on 4 Nov 2005 08:10:32 -0800
<1131120632.525738.25640@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>:
> 23. The Ghost In The Machine
> Nov 3, 6:00 pm show options
>
> Newsgroups: sci.physics.relativity
> From: The Ghost In The Machine <e...@xxxxxxxxxxxxxxxxxxxxxxx> - Find
> messages by this author
> Date: Fri, 04 Nov 2005 02:00:05 GMT
> Local: Thurs, Nov 3 2005 6:00 pm
> Subject: Re: OWLS & Out of Sync Clocks-By How Much Are They Out of
> Sync.
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> In sci.physics.relativity, kens...@xxxxxxxxxx
> <kens...@xxxxxxxxxx>
> wrote
> on 3 Nov 2005 07:57:46 -0800
> <1131033466.893845.57...@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>:
>
>
>
>> OWLS can be anything....that's why you had to masure it.
>> The 299,792,458m/sec is a TWLS value by defintion.
>
> Ghost:
> No, it is not. It is using light-defined length (that's
> why it's constant, if I understand your theory correctly).
>
> Ken:
> That's by definition. TWLS is defi9nd as 1 light second/1 clock second
>
> Ghost:
> A true TWLS would use stationary length.
>
> Ken:
> That's true.
>
> Ghost:
> But OK, dumb question #2: what does TOWLS (not to be confused
> with LDOWLS) depend on? Velocity of the source, for example?
> Or perhaps the curvature of surrounding space? Or what?
>
> Ken:
> I don't know what you mean by TOWLS or LDOWLS mean.
True One Way Light Speed (OWLS measured using a standard ruler);
Light-Defined One Way Light Speed (OWLS using a light-defined ruler,
and therefore constant by definition).
>
>> You asked: Why would OWLS be isotropic?? The answer: the absolute
>> motion of the earth wrt the local light rays is in the vertical
>> direction.
>
> Ghost:
> What speed?
>
> Ken:
> You need to measure it as described in my pdf file. OWLS is distance
> dependent.
Do you have a formula for OWLS given the distance? Something along
the lines of t = ((d-lambda)/c), if one assumes the first wave
misses the aperature completely?
>
> Ken Seto
>
--
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