Re: Cubic Complex Variables / Applications

Symmetry Observer:
>
>Bilge wrote:
>> Symmetry Observer:
>> >
>> [...]
>> >
>> >L = (1/2)*c^2/a_o
>> >(eq.6)
>>
>> a = (c\alpha)^2/a_0 = 9.45 x 10^22 m/s^2
>>
>> >A quick calculation will show that L is indeed sufficiently large to
>> >be considered as a candidate for the universal acceleration limit.
>>
>> Nowhere close. A proton or neutron in a generic nucleus has a
>> characteristic acceleration about a factor of 10^8 larger than
>> that.
>
>I am using
>
>c = 3.0 x 10^8 meters/sec (approximately)
>
>a_0 = 5.29 x 10^ (-11) meters (approximately)

The radius of a nucleus is approximately (1.5 fm) x A^1/3 and a
crude estimate of the average kinetic energy of a nucleon is about
8 MeV. Figure it out for 3He. You have a radius of that's a factor
of 10^4 too big.

>I emphasized before that this was only a preliminary estimate. Since
>you mentioned
>typical proton or neutron accelerations in a generic nucleus, I will
>have to review the
>constants of nature associated with QCD. I wonder if the fact that the
>QCD

Why? There's no point, since (1) acceleration and velocity aren't
good quantum numbers anyway, so the velocity and acceleration are
only of heuristic value, (2) the actual numbers would vary widely
depending on the exact atom or nucleus in question, (3) the only
velocity eigenvalue of the dirac equation is `c'. Any other velocity
is really just an expectation value of the zitterbewegung. (4) Since
an electron (or nucleon) which is in an eigenstate, is in a stationary
state, the velocity doesn't make sense as anything but an analogy,
and only then, when the analogy is valid.

>accelerations and the "L" accelerations are both short ranged is a co-
>incidence.

Unless ``L'' means angular momentum, pick another letter - preferably
one that isn't ubiquitously associated with a specific quantity.

.

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