Re: Lienard-Wiechert potential
- From: "Ken S. Tucker" <dynamics@xxxxxxxxxxxx>
- Date: 16 Dec 2005 06:50:13 -0800
David McAnally wrote:
> There was some confusion a while back about the part that the Lienard-
> Wiechert potential of an accelerating charge plays, so I thought that I
> would clarify.
hmm...ok
[snip]
> In the case of an instantaneously stationary charge q accelerating with
> acceleration a, integration of the long-distance Poynting vector over a
> sphere demonstrates that the charge is losing energy to radiation at the
> instantaneous rate of q^2 a^2/(6 \pi e_0 c^3) = m_0 q^2 a^2/(6 \pi c),
> i.e. the instantaneous power being supplied by the charge to the radiation
> is q^2 a^2/(6 \pi e_0 c^3).
Radiation is Quantized, and in particular, that is certainly a
necessary detail at the "point charge level".
McAnally's result predicting a continuous rate of energy and
power output via radiation is NOT correct, hasn't been since
1900, something to do with photons.
Overall his classical approach looks good, however since
McAnally loves to kill-file people who find technical errors
in his posts, like me, I'll leave the quantum correction of
his argument to another poster, who will be subsequently
kill-filed.
Ken S. Tucker
.
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- From: David McAnally
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