Re: Three Ring Circus
- From: "PD" <TheDraperFamily@xxxxxxxxx>
- Date: 30 Dec 2005 07:00:48 -0800
skearney@xxxxxxxxxxxxx wrote:
> Imagine three rings, side by side, with maglev tracks on the inside
> surface. Trains run on these at gamma two (86.6% the sol), seven and
> twentysix, so that, to an observer stationary to the tracks, their
> length contraction and time dialation are 2, 7 and 26 respectively.
> As I understand it, an observer on the first train will see the
> trains on the second and third tracks as being contracted and time
> dilated by a factor of two and seven respectively. An observer on the
> second track train will see the train on the third as being contracted
> by two and likewise the train on the first track, only in the opposite
> direction.
> Now suppose there are clocks on all the train cars. Wouldn't an
> observer on any of the trains find the time measured by the clocks on
> the other trains inconsistant with his relativistic calculations?
You realize, of course, that none of these are inertial frames.
Would it be sufficient for your purposes if they were on side-by-side
tracks, all passing each other at the same point on the track at a
moment in time?
PD
.
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