Re: Understanding the Lorentz transformations
- From: "Der alte Hexenmeister" <vanquish@xxxxxxxxxxxx>
- Date: Fri, 30 Dec 2005 23:22:50 GMT
"Sue..." <suzysewnshow@xxxxxxxxxxxx> wrote in message
news:1135960557.952394.263730@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Der alte Hexenmeister wrote:
> "xray4abc" <lemhenyil@xxxxxxxx> wrote in message
> news:1135904424.169741.104340@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
> > Hi , everybody in this group
> > Let's consider light propagation along the x-axis
> > to left and to right from a given point in 2 relatively moving IRS.
> > At any time ,in any of the considered IRS, light travels
> > equal distances to left and to right.
> > Now, in the 2 IRS the law of light propagation is x=ct and
> > x'=ct' respectively.
> > The relation between x and x' is given by the Lorentz transformation.
> > Now, my question is :Does the Lorentz transformation give the
> > equal left and right distances as it should?
> > It seems to me ,at first sight, that it does not.
> > Am I wrong?
> >
> > All the bests for you guys in the coming year !
> > Happy New Year!
> >
> > LL
>
> tau = (t-vx/c²)/sqrt(1-v²/c²)
> tau = (t-uy/c²)/sqrt(1-u²/c²)
> tau = (t-wz/c²)/sqrt(1-w²/c²)
> xi = (x-vt)/sqrt(1-v²/c²)
> eta = (y-ut)/sqrt(1-u²/c²)
> zeta= (z-wt)/sqrt(1-w²/c²)
> If one is right they all are, if one is wrong they all are.
> Carry three watches or do not move sideways or ride an elevator.
Drop the watch and move however you please.
*** " as judged from K " ***
http://www.bartleby.com/173/12.html
I PLACE three metre-rods in the x'-axis of k', the y'axis of k', the z'axis
of k'
in such a manner that one end (the beginning) coincides with the point x' =
0,0,0, whilst the other end (the end of the rod) coincides with the point x'
= 1,0,0,
another rod end (the beginning) coincides with the point y' = 0,0,0, whilst
the other end (the end of the second rod) coincides with the point y' =
0,1,0,
a third rod end (the beginning) coincides with the point x' = 0,0,0, whilst
the other end (the end of the third rod) coincides with the point z' =
0,0,1.
What is the length of the three by one metre-rods relatively to the system
K?
In order to learn this, we need only ask where the beginning of the rods and
the end of the rods lie with respect to K at a particular time t of the
system K. By means of the first equation of the cuckoo transformation the
values of these six points at the time t = 0 can be shown to be
x(beginning of rod) = 0.sqrt(1-v²/c²)
x(end of rod = 1.sqrt(1-v²/c²)
y(beginning of rod) = 0.sqrt(1-u²/c²)
y(end of rod = 1.sqrt(1-u²/c²)
z(beginning of rod) = 0.sqrt(1-w²/c²)
z(end of rod = 1.sqrt(1-w²/c²)
---- yada yada yada.
Little witch, visit Diagon Alley for new text books, the
necromancer Einstein is boiling and bubbling in my cauldron.
I'm serving him up for Eye of Newt stew.
Androclese,
You are doing a "heck of a job"
http://www.google.com/search?hl=en&q=%22heck+of+a+job%22&btnG=Google+Search
The correct title and name is Professor Androcles Dumbledore,
please address to "Headmaster of sci.physics.hogwarts".
I receive all email via OWLS.
Der alte Hexenmeister.
:-)
Sue...
Sue...
>
> Der alte Hexenmeister.
.
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