Re: I need someone's brain juice here?
- From: guskz@xxxxxxxxxxx
- Date: 30 Dec 2005 23:10:51 -0800
Joe Fischer wrote:
> guskz@xxxxxxxxxxx wrote:
>
> >
> >Tks Joe, actually the first one (other than the mercury model) has two
> >pressures P1 and P2 and not nescessarily atmospheric pressure.
>
> In one of the images after the first one, yes, with
> air flowing through the orfice at the top.
> I think that complicated the presentation, the same
> thing could have been done with just a straw.
>
> The whole thing was a big science lesson, way too
> much just to convey the concept of pressure differences.
>
> I see no reason that any two equations should
> coincide, I am not even sure that all the variable identifiers
> are clear to the student.
>
> I didn't see a variable identifer list, but there may
> be one, it is too much to ask for all visiters to the site
> to know p might stand for density instead of pressure,
> and g stands for a _nominal_ value of acceleration
> instead of an actual acceleration at a given location.
>
> So if you still feel you have a question, try to
> describe it better (the links don't always point to
> a specific place on a page).
>
> Glad to see some interest in understanding
> what is presented.
>
> Joe Fischer
Basically Joe both models seem the same,both have two pressures applied
on either side which determine the final heights of the fluid in each
tube.
#1 h = h2 -h1 and #2 h = d1 + d2
h1 & h2 is in relation to the base of the fluid and d1 & d2 is in
relation to the initial height if both pressures applied are the same.
yet h in #1 will not give the same value for h in #2 ....could it be
because the fluid's weight is higher than the pressures applied in #1
thus giving a completely different equation?
If so it's strange since equation #1 is indeed Bernouilli's equation so
it should also apply to #2
Bernouilli with fluid velocity = 0
thus P1 + pgh1 = P2 + pgh2
thus P1 = P2 + pg (h2-h1)
thsu P1 = P2 P pg (h) (where h = h2-h1)
.
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- From: Joe Fischer
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