Re: Why TWLS= 0 <> OWLS in any ONE Frame.


"sal" <pragmatist@xxxxxxxxxx> wrote in message
news:pan.2006.01.31.03.00.44.970931@xxxxxxxxxxxxx
> On Mon, 30 Jan 2006 15:34:08 -0600, Tom Roberts wrote:
>
>> sal wrote:
>>> "scalar" is often -- perhaps usually -- taken to mean "scalar field
>>> on the manifold" and hence something which is also "invariant", or
>>> independent of choice of coordinates.
>>
>> Yes. A real-valued field on the manifold (occasionally a complex
>> value is used).
>>
>>
>>> Time's not, so time's not a scalar, either.
>>
>> Well, be careful. The time coordinate of a specified observer _is_ a
>> scalar field on the manifold.
>
> Yes, of course, you're right, at least as long as we stick with SR.
> In GR, where particular coordinate systems may cover a subset of the
> manifold, the statement is a little less clear-cut.
>
> And of course we shouldn't forget that other neglected invariant,
> either: the relativistic mass (OH NO NOT THAT!): the inner product of
> the 4-momentum of an object with the 4-velocity of a particular
> observer is the mass/energy of the object, aka relativistic mass, as
> measured in that observer's rest frame.... so, since the inner product
> of two vectors is an invariant, so's the (frame-dependent)
> relativistic mass.
>
>
>> Specifically: for observer A, observer A's coordinates apply a real
>> value t_A(P) to every point P of a given region of the manifold, and
>> is therefore a scalar field on that region; all observers will agree
>> that A's time coordinate has the value t_A(P) at each point P in
>> that region (of course different observers will naturally use
>> different time coordinates; that's irrelevant).
>>
>> This has been called an "observer-dependent invariant", which
>> about sums it up.
>>
>> In the abstract, "time" without specifying an observer has no
>> meaning in relativity (or at least no _observable_ meaning).
>
> If a tree falls in the forest and nobody's there to observe it ....
> what makes you think it really fell?
>

You come along "later" (a time word) and find a dead theory tree
"lying" as usual.

c is a vector, -c is a vector,
c-c = c when 2AB/(t'A-tA) = c because nobody knows what tB is.
Find out. Ask Cassini the time.
http://www.androcles01.pwp.blueyonder.co.uk/Synchronize/Synchronize.htm

It is so, so nice to see two in-denial grieving shitheads in a kook fight.

Androcles Dumbledore, B.A., M.Sc., Ph.D., N.R., F.R.S., Queen's Award for
Export and Technology, Headmaster - hogwarts.physics, der alte
Hexenmeister.

PS. We all impressed by fancy titles, right?
N.R. is Necromancer of Relativity. F.R.S. is Flight Really Simulated,
and should not be confused with Fellow of the Royal Society.
http://en.wikipedia.org/wiki/Queen's_Award_to_Industry
That award and 50 cents bought me a cup of coffee in McDonalds,
which wasn't quite so expensive in 1984. I'm not too sure if the two
quarters carried the greater weight or not, the little gal who served me
seemed impressed by my blue tie and yellow emblem to the point
of asking me what it was.

PPS. "Necromancer" is a wiz wurd for the muggle equivalent
"Pathologist". A. Dumbledore exhumes dead theories and autopsies
them to see why they are past their expiration (or sell-by) date.
We can't have dead theories walking, they stink like tords.

"Dr. John Parker" is a pseudonym for the sole purpose of the muggle
electoral register, used by
Androcles Dumbledore, B.A., M.Sc., Ph.D., N.R., F.R.S., Queen's Award for
Export and Technology, Headmaster - hogwarts.physics, der alte
Hexenmeister.

http://www.androcles01.pwp.blueyonder.co.uk/


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