Re: Just what is SR?
- From: "Hexenmeister" <vanquish@xxxxxxxxxxxx>
- Date: Mon, 20 Feb 2006 08:37:18 GMT
"xray4abc" <lemhenyil@xxxxxxxx> wrote in message
news:1140406279.478939.89950@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Dirk Van de moortel wrote:
What these equations do, is to give the coordinates x' and
t' for an arbitrary event in spacetime, event for which the
coordinates x and t are known. That is what a coordinate
transformation does.
The x and t in the equations define an arbitrary event in
spacetime. One can pick any combination of x and t to
define an event. So x and t are independent quantities.
Any dependency that you impose upon them, results in
your considering a mere subset of spacetime - for instance
a world line of some particle or light signal.
As soon as you fully agree on this, we can continue and
I will reply to the remainder of your message.
Dirk Vdm
I am sorry, but we speak differently the language of physics.
Don't be sorry. Kick the idiot in the balls.
He's just squawked like a parrot yesterday:
" Polly want a kwacker
http://physics.nist.gov/cuu/Units/second.html
The second is the duration of 9192631770 periods of the
radiation corresponding to the transition between the two
hyperfine levels of the ground state of the cesium 133 atom.
Polly want a kwacker"
-- Dirk Vdm
For the first time in his life he didn't mumble "time is what a clock says"
or try to tie it to the velocity of radiation, but to the count.
Give him his cracker and forget his other squawks.
I have pondered over the subject quite a long time since last year
and I can see it now, I would say, more realistically.
You have the liberty of choosing an x axis and specifically
its
reference point. From there, and from the liberty of choosing the time
and length units, results the liberty of " picking the combination
of x and t to define an event".
Once you have done this, you just have the liberty of choosing
the start moment of a measurement on a moving object.
That means, you can not possibly know x' and t', as they relate to the
moving system, which is beyond your direct access.
Your x and t result then from measurements you have no control
on, except the things mentioned above.They are what they are.
The Lorentz transformations give, exactly what they meant for Lorentz
himself, a means to calculate quantities related to a moving object
( or IRS) from measurements done in our resting IRS using
an interaction with the object of the measurement.
To cut it short, I do not say that the Lorentz transformation
do not apply !
Well it, doesn't.
What I am saying is, that there are limits that
should be considered.
Yeah, The same limits that apply to driving a London bus underwater
on a methane and oxygen mixture. It doesn't work, and if it did
it would make bubbles and scare the fish.
I do not impose any dependency or
limits on the coordinates. The nature of the measurements does !
( It does in quantum physics, doesn't it?)
All the best, LL
Come off it. You are just saying "all the best" to kiss arse.
Everyone knows you don't really give a ***, so why say it?
I'm polite to people that are honest. *** the rest.
Androcles.
.
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