Re: I'm Not Sure if this Worries Me or Not.
- From: "PD" <TheDraperFamily@xxxxxxxxx>
- Date: 8 Apr 2006 23:55:47 -0700
Henri Wilson wrote:
On 7 Apr 2006 21:32:48 -0700, "PD" <TheDraperFamily@xxxxxxxxx> wrote:
Henri Wilson wrote:
On 5 Apr 2006 06:05:48 -0700, "PD" <TheDraperFamily@xxxxxxxxx> wrote:
That's a TW measurement.
No.
I want a direct OW measurement.
It can be doenin a circular path such as a cyclotron.... but you said it can be
done in a free linear beam.
Yes. Don't be an idiot:
V
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= Detector 1 --- delay line to common timer
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| common timer
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= Detector 2 --- delay line to common timer
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V
One linear path of electron pulse. Two detectors. Signals from
detectors sent through two identical-length cables to two timers or to
one start-stop timer. The time of flight is *timed*. I cannot believe
that you cannot figure out how this works.
Ask Tom Roberts to explain it to you. Tell him that v is close to c.
I don't need it explained to me. I'm trying to draw it for you as a
means of explaining it to you. You keep talking about this being a TW
measurement or a round-trip for the electron. It is neither.
Did you not know that it is fairly straightforward to measure the time
of flight of a single pulse through two widely separated detectors? (It
is not my method, note. It is so mundane that it is commonly given as a
basic exercise to young HEP students to set up the equipment and the
electronics to measure that time of flight. I see that you have never
been give that opportunity, which is perhaps why you are so prone to
saying ridiculous things about how nature behaves in real life.)
Coincidence methods are TW.
No, they are not.
You have to synch the detectors with EM to get the
right delay times.
No, you do not. You can send the signals from two detectors through
identical length cables to a common receiver between them. The time
between the arrival of the two signals is measured by a TDC, or a
start-stop latch timer, or even by fanning the two signals into a
single oscilloscope input, or any of a whole slew of possible
configurations.
You, sir, are uninformed and stubbornly so.
Ask Tom Roberts why this is a TW experiment if the speeds are near c.
Clue: you cannot assume light speed is the same in the cables irrespective of
their layout.
Who said anything about light speed in cables? The speed in the cables
could be 0.62c. The fact that the delay along the cables is the same is
the only thing we need here.
I'm not talking with Roberts. I'm talking with you.
PD
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