Re: GR frequency shift formula
- From: mluttgens@xxxxxxxxxx
- Date: 12 Apr 2006 02:51:41 -0700
Sue... wrote:
mluttgens@xxxxxxxxxx wrote:
Sue... wrote:<< What does GR predict for a cesium clock located in
vanep@xxxxxxx wrote:
snip
The correction is ~38,500 nanoseconds/ day.
Almost right!
The GR formula gives the approximate prediction correctly. Your formula
is incorrect by over 2000 nanoseconds/day. Using your correction would
result in the GPS being off ~ 615,4 meters/day.
http://www.phys.lsu.edu/mog/mog9/node9.html
hollow in the center of the planet ? >>
Marcel Luttgens:
Sue...
<<
My formula, which takes the relative velocity of the satellite based
and Earth based
clocks into account, reduces to
Nu2/Nu1 = 1 + M2*(1/R2-1/d-1/2d)
Shift = Nu2/Nu1 - 1 = 3.66E-10, which is the correct value.
Multiply the shift by the day in nanoseconds (8.64E10), and you get ~
31.6 nanoseconds/day. >>
"What does GR predict for a cesium clock located in
hollow in the center of the planet ?"
Sue
I have no idea of what GR would predict.
As for me, the shift is -3.47E-10
Marcel Luttgens
You seem to be saying it would run slower than a
a clock at the surface at a point with less gravity
than at the surface. Hmmm ?
Sue...
The shift is of course 3.47E-10 !
Marcel Luttgens
My formula, which takes the relative velocity of the satellite based
and Earth based
clocks into account, reduces to
Nu2/Nu1 = 1 + M2*(1/R2-1/d-1/2d)
Shift = Nu2/Nu1 - 1 = 3.66E-10, which is the correct value.
Multiply the shift by the day in nanoseconds (8.64E10), and you get ~
31.6 nanoseconds/day.
The value is 38 thousand 5 hundres nanoseconds/day.
http://www.eftaylor.com/pub/projecta.pdf
Notice that my reduced formula is identical to the GR approximate
formula.
Your formula is garbage. If it was identical to the GR formula it would
make a prediction that was incorrect by over 2000 nanoseconds/day.
Using your formula the GPS would have crashed and burned in a couple of
minutes.
Seemingly, you have a problem with simplifying a formula.
You can't even convert your scientific notation to nanoseconds. You
seeminly think your formula predicts a delta of 31.6 nanoseconds/day.
Clearly you must know the GPS is completely functional and the
correction was made using GR so what logic leads you to make the
comment "Clearly, GR is a very poor tool"?
GR can only solve simple cases, like the GPS one.
Remember that to my question
"Do I have to conclude that GR cannot numerically solve this elementary
problem where
M1 = M* ( M* = 1 solar mass), R1 = 5 Km, M2 = 5 M*, R2 = 20 km, d = 50
km ?",
Folks who understand relativistic physics know what the difference is
between the weak and strong gravitational field. GR certainly is a poor
tool for you because you never read the operations manual. If we were
talking about a chain saw you would have cut off your leg.
Tom rightly answered
"No. But there is no useful approximation that applies, and this is a
quite complicated computation that can only be performed via numerical
simulation.",
whereas my formula at least gives straightforwardly an approximate
solution (Nu2/Nu1=0.9). If you are skeptical, perform the numerical
simulation.
Your formula is wrong. It doesn't give he right answer for the GPS.
If you could (what I doubt), you should obtain ~0.87.
As long as GRists content themselves with generalities or easy slogans,
they will not be taken seriously.
They will never be takin seriously by cranks such as yourself..
Marcel Luttgens
.
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