Tree Paradox
- From: "eleaticus" <eleaticus@xxxxxxxxxxxxx>
- Date: Sun, 16 Apr 2006 00:36:31 -0500
Let there be a space-going tree, the gedanken-virtue of which is that it
grows more rings at a regular, relatively frequent rate. It and its rings
are perfectly symmetrical around its long axis, and it is headed in the
direction of its long axis straight onto the cutting end of a large-enough
ax head that will perfectly halve the tree along the long axis, killing the
tree and stopping the ring growth.
Let there be a 'station' at rest with respect to the ax-head observers to
which the tree communicates its number of rings as it narrowly passes the
station.
The tree, having previously been in the unchanging neighborhood and with
perfect knowledge of itself knows that it will grow exactly 120 more rings
before it gets chopped and dies.
Relative to the station the tree is moving at v~.94281c, so gamma=3 in the
station's view.
Therefore the station Relativists know darn well that time has slowed for
the tree to just a third of the station time.
The number of new rings at chop-time, thus, must be only 40.
Relative to the tree another observer is approaching from the opposite
direction at v~.96824c relative to the tree, so gamma=4 with respect to the
tree in its view.
The number of new rings at chop-time, thus, must be only 30.
Relative to the tree another observer is receding from the tree along the
tree's vector so that the net is v~.866c, so gamma=2 with respect to the
tree in its view.
The number of new rings at chop-time, thus, must be only 60.
As the tree commits hari-kari on the ax the ax begins the emission of such
strong lights in relevant directions that the two moving observers can
accurately see the tree rings and count them, and, of course, the station is
busy transmitting the number of rings the tree had before it began the
growth of the 120 new rings.
So, question, these figures being straight Special Relativity dogma, how
many new rings are counted/observed by each of:
A. the ax's observers
B. the approaching observer
C. the receding observer
ROFFLMFAO!
Surely you don't think that Special Relativity's time dogma isn't complete
nonsense? Only one answer is possible because there was only one tree doing
only one time-thing and the tree knew that answer all along.
The paradox isn't the contrast between the nonsensical SR time dilation
effects, it is that otherwise(?) intelligent people could maintain their
cult beliefs once they are released from thrall to their professors.
If there is a time effect of motion it can't be Special Relativity's.
See also "Einstein's dilation derivation: ROFFLMFAO!"
That article will show you, using Einstein's own method, how silly it is to
reach any conclusion about time effects based on Einstein's
t'=gamma(t-vx/cc).
eleaticus
ee-lee-AT-i-cus
.
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