Re: Tree Paradox


"RP" <no_mail_no_spam@xxxxxxxxx> wrote in message
news:1145223124.200068.313200@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

eleaticus wrote:
The tree, having previously been in the unchanging neighborhood and with
perfect knowledge of itself knows that it will grow exactly 120 more rings
before it gets chopped <by the 'stationary' ax> and dies.

Redundant, all observers will predict the same number of rings.

Relative to the station the tree is moving at v~.94281c, so gamma=3 in
the station's view.

Therefore the station Relativists know darn well that time has slowed
for the tree to just a third of the station time.

The number of new rings at chop-time, thus, must be only 40

No it mustn't. Wrt the station observer the distance traversed is 3
times greater, thus offseting the slowed growth rate exactly and
allowing time for 120 rings to grow during the tree's travel at v.

In general, and in particular, I very much appreciate your response.

In the particular, because you bring up the two views of the distance, which
I make much of in a post elsewhere and which will show up here in many
segments..

But, you do realize that you are saying that if the tree synchronizes clocks
with the station which is synchronized with the ax, that the tree's clock
will show the same time as the ax's clock upon the tree's arrival at the ax?

And that an initially synchronized travelling twin will arrive at a site
that has its clock synchronized with his stationary twin's and find that his
clock reads the same as the site's and his twin's, and that when he returns,
completing the round trip, his clock will read the same as his twin's?

And you do realize that you come close to saying the whole gamma bit is
wrong?

That if light travels at c and you and gamma are correct then any distance
it travels should be contracted in its view to at least close to zero so, by
your logic, in the statioanry observer's view the light has to travel for a
distance damn near infinitely greater than the light 'thinks'? Which would
make c damn near infinite?

The least that could be said, if you are right in saying the stationary view
is that the moving object has to travel the stationary object's distance, is
that if you let light travel without its own space-contraction then you have
to discard gamma as universal law.

Only what the ax sees should be counted in what the ax sees. Only what the
tree
sees should be counted in what the tree sees.

eleaticus
ee-lee-AT-i-cus


.

Relevant Pages

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