Re: SRian 'events' versus SRian dilation: ROFFLMFAO!
- From: "eleaticus" <eleaticus@xxxxxxxxxxxxx>
- Date: Thu, 20 Apr 2006 13:41:58 -0500
Responding to my demonstration that, using the
elapsed-time-interval-between-'events' formulations, the moving system
elapsed time, T', was (A) T'=gamma*T in the case of the purest 'time-like'
interval (showing contraction, not dilation) and (B) T'+gamma(v x2/cc - v
x1/cc) = gamma*T in the case of 'space-like' intervals (showing even more
contraction), Paul B. Andersen 'proved' me wrong by showing once again that
such formulations result in contraction rather than dilation:
"Paul B. Andersen" <paul.b.andersen@xxxxxx> wrote in message
news:1145544274.800330.317380@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
The SR-dogmatic dilation in your scenario is T = T'/g.
(The above followed the next quoted material as an explanation of what he
thinks he showed.)
This can be illustrated by letting the tree be "stationary",
and the axe be moving:
(assuming the axe is moving in the postive x' direction)
t1 = g(t1' - v x1' /cc)
t2 = g(t2' - v x2' /cc)
t2 - t1 = g((t2' - t1' ) - v (x2' - x1' )/cc)
Now we have:
(x2' - x1' ) = v (t2' - t1' ) (length = speed * time)
t2 - t1 = g( (t2' - t1' ) (1 - v v/cc)) = (t2' - t1' )/g
T = T'/g or T' = gT
Let that be equation (C).
Let M be the moving system elapsed time, and S the stationary system elapsed
time.
Since he used the primed values as stationary system values we have:
(C') gS = M
(A') gS = M
(B') gS = M + g( v x2.s/cc - v x1.s/cc )
He says a time or two "both sets will show the same result".
Yes, time contraction for the moving system..
ROFFLMFAO!
Beyond such an astounding proof that I was wrong, there was one other item
of interest in Paul's resounding defense of SR's dilation nonsense:
Your confusion is that you don't understand what is meant
by the phrase "a moving clock is running slow".
Look at what your scenario is.
You are comparing one clock C, to two _different_ clocks A and B.
T is the difference between two readings _of the same clock_,
while T' is the difference between two readings on _different_ clocks.
T is a proper time, T' is not.
That defense (which is particularly silly because you actually think you
showed me wrong with your proof that I was right) is actually "incompetent
observer" babble.
The moving system's two clocks you refer to are synchronized. If the two
clocks communicated after the facts using even straight classical time they
would agree on the time of both events. But you act as if the moving system
observers are ignorant idiots* and perhaps don't even know their clocks are
synchronized and thus act as ONE gigantic clock readable at any location in
that system.
If your immediately above were pure babble you would not have shown gS=M, as
you did, to prove me wrong in saying gS=M.
* which they probably aren't if they aren't Relativity cultists.
eleaticus
ee-lee-AT-i-cus
.
- Follow-Ups:
- Re: SRian 'events' versus SRian dilation: ROFFLMFAO!
- From: Paul B. Andersen
- Re: SRian 'events' versus SRian dilation: ROFFLMFAO!
- From: Dirk Van de moortel
- Re: SRian 'events' versus SRian dilation: ROFFLMFAO!
- References:
- SRian 'events' versus SRian dilation: ROFFLMFAO!
- From: eleaticus
- Re: SRian 'events' versus SRian dilation: ROFFLMFAO!
- From: Paul B. Andersen
- SRian 'events' versus SRian dilation: ROFFLMFAO!
- Prev by Date: Re: square root operator?
- Next by Date: Re: SRian 'events' versus SRian dilation: ROFFLMFAO!
- Previous by thread: Re: SRian 'events' versus SRian dilation: ROFFLMFAO!
- Next by thread: Re: SRian 'events' versus SRian dilation: ROFFLMFAO!
- Index(es):
Relevant Pages
|