Re: Is Nuclear Bomb's energy exactly = seperation of two charges (fission)??


PD wrote:
guskz@xxxxxxxxxxx wrote:
Tom Roberts wrote:
guskz@xxxxxxxxxxx wrote:
Is a Nuclear Bomb's energy exactly = seperation of two charges
(fission) TIMES the number of paired charges (chain reaction)?

No. Many times larger. Because in nuclear fission the strong force is
involved, not just the electromagnetic force.

Ok but where does this strong force suddenly come from meaning:

Does a hydrogen atom have this strong force since its only a proton and
electron (no nucleus), isn't the force between an electron and proton
pair only electro (electric charge)and magnetic?

That's right, a single hydrogen atom has no binding energy due to the
strong force. (Except the binding energy between the quarks in the
proton.) In a *fusion* bomb, however, there is binding energy recovered
from the coalescence of protons and neutrons.




Indeed, after things settle down after a nuclear explosion, there is no
net separations of electromagnetic charges, but the nuclei have been
re-arranged such that a large amount of energy was released, in the form
of gamma rays, neutrons, nuclear debris, and their kinetic energies.


If so how logically can binding energy be used to produce energy,
meaning you have a proton and an electron(or a pair of attracted
magnets) attracted to each other, then simply by distancing them
(seperating them) produces external energy ouput?

You are confused.

A U^235 nucleus has a certain total mass. To produce energy from the
nucleus, you must arrange for the U^235 nucleus to fission, yielding a
set of smaller nuclei the sum of whose masses total less than that of
the initial U^235 nucleus. The difference M(U^235)-M(fission products)
is the kinetic energy of those products, and that is "produced" by the
fission. No energy is created here, it's just that the U^235 nucleus was
used to store energy from some ancient star/supernova, and a portion of
it gets released in this fission.

Since binding energy is necessarily negative,

I'm not familiar of the "logic" of where binding energy comes from "IF"
you are only dealing with protons and electrons (electro and magnetic
forces) since even the nucleus (where this binding energy resides) I
believe I once read they said that a neutron "may" simply be one
electron and proton paired together?

That would be an incorrect statement. The neutron is *not* an electron
and a proton paired together. If it were, the neutron would be the size
of a hydrogen atom, and it would take very little energy (about 13.6
eV) to tear a neutron apart.

PD

Thanks PD very good and concise reply



those fission products are
in toto more strongly bound than the original nucleus. This is true of
all exothermic reactions, be they nuclear, chemical, or weak -- to
release energy the products of the reaction must in toto be more tightly
bound than the initial components.


Tom Roberts

.

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