Re: An IITJEE problem
- From: "N:dlzc D:aol T:com \(dlzc\)" <N: dlzc1 D:cox T:net@xxxxxxxxxx>
- Date: Thu, 27 Apr 2006 17:32:01 -0700
Dear Nishu:
"Nishu" <amitk_dni@xxxxxxxxxxx> wrote in message
news:1146152710.843745.302370@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
I have a SHM problem.
"Simple Harmonic Motion"
A rod of length L is placed on two circular dics.
The co-efficient of friction between rod and disks
is k. The rod is displaced by a small distance x.
Determine the time period of the oscillations.
_______________________
O O <----disks
<-------------- L ----------------->
The answer is t = 2??(L/2kg) [g- acc due to gravity)
But I want the solution.
The problem setup is lacking much. I assume the disks are acting
like wheels, so there would be no SHM. Your formula gets trashed
if you do not use ASCII.
Is this t = 2 . pi . sqrt( L / (2 . k . g) ) ?
David A. Smith
.
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