Re: What Exactly Happens to TIME in GPS Orbit?
- From: "Rudolf Drabek" <newsrudy@xxxxxx>
- Date: 5 Jun 2006 10:13:38 -0700
Henri Wilson schrieb:
On 1 Jun 2006 16:54:22 -0700, "Rudolf Drabek" <newsrudy@xxxxxx> wrote:
Henri Wilson schrieb:
On 1 Jun 2006 07:22:59 -0700, "Rudolf Drabek" <newsrudy@xxxxxx> wrote:
Henri Wilson schrieb:
Relativists claim that GPS clock remain unchanged when sent into orbit. Theyo.k. no snipping.
seem to think that something happens to TIME itself and this causes the clocks
to appear to run fast when seen from Earth.
Could one of the experts from the lunatic fringe please explain this process in
greater detail. There are aspects of it that are a little hard to follow.
HW.
www.users.bigpond.com/hewn/index.htm
Appropriate message snipping is considerate and painless.
Once Larry Hagman was asked what's the difference between Dallas and
Texas: 1 mile he said.
Indeed a clock in Denver advances 108 ns per week compared to Southfork
ranch.
Well why don't they fix the bloody thing?
But you can also accept the Moessbauer effect or make the above
mentioned experiment in a higher building with 2 atomic clocks or other
stable references.
The Pound-Rebka experiment shows that the Gravitational blue shift is due to
light accelerating down a gravity gradient.
The magnitude is exactly the same as that predicted by GR, using constant light
speed and distorted space..... that is not at all surprising.
Would like to know if you can explain the results carried out by you!
The time differences are quite big, so no problem with accuracy.
At least one clock is wrong.
You try to sqeeze out: You can exchange the clocks.
The clocks are adjusted to show no significant phase diff. after one
week of observation.
At least one magnitude lower than the expected/measured result.
Come on! You know that has never been proved to within experimental error.
They both should emit the same number of ticks per EARTH ORBIT PERIOD.
That is wrong but to make it simple I have taken stationary clocks to
eliminate the velocity error. Assume and verify that from two clocks
the one, that is higher -e.g. on top of a high building- is advanced
compared to that at ground floor. As a fact there is no rel movement
between them.
The top one is experiencing less internal compression due to the weaker
gravity.
What is that?
It is also cutting the Earth's fields at a faster rate.
What? earth field gravity? If you agree, then you agree in GR.
I ask you first to stick to the experiment and explain it with your
theory.
If a clock emits more ticks per 'Earth day' when it is raised to a higher
position, it has obviously changed physically.
I think we let it.
The clocks do not change their properties. It's easy to check. You can
exchange the clocks for the same time -e.g. 1week- they have been
separated so after -e.g. 2 weeks- they are again synchronized when
brought together.
Another point that I can accept is, that if you are mixing frames you
can calculate SOL > c. But this is not of belong for stationary clocks.
One Way SOL can have virtually any value, depending on the relative
source/observer speed.
Rudi
HW.
www.users.bigpond.com/hewn/index.htm
Appropriate message snipping is considerate and painless.
HW.
www.users.bigpond.com/hewn/index.htm
Appropriate message snipping is considerate and painless.
.
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