Is there any evidence that 1G is not a universal coefficient?

Is there any evidence that 1G is not a universal coefficient?

I ask this question because "relativity" requires a point of reference.
Einstein says that from the Newtonian base (F=MA), uses the speed of
light as the reference point to the relativity of M.

Therefore what would A (acceleration) use as the reference point for
relativism?

Would E=A(G squared) make sense as the equivalent to E=M(C squared)?

I am not a mathematician. But I am attempting to say that A and G do
not maintain the same fixed relation in space, where G=0.

The weightless trick in the astronaut training aircraft is because:
-1A + 1G = 0G
That is saying that A=G when A is 9.8 M per second squared.
So is A is for examples 98M per second square performing the same
trick:
-10A + 1 G = 9G

What if 1G is a universal coefficient? No evidence of life beyond our
planet is a good starting point for a universal coefficient. That is to
say future evidence of humanoid or intelligent life could in theory be
found only to exist on 1G planets. If life is found on non-1G planets,
unless it is intelligent enough to have a language to attach meaning to
the term "coefficient", that would not mean that 1G was not a
universal coefficient.

In that case, the relationship of E=M(C squared) to F=MA could be the
same as E=A(G squared). The substance being that as C (the speed of
light) cannot be surpassed no matter how great F is because the
increase in M is exponential. Therefore for a "relativity of natural
gravity" the G (the natural gravity) cannot be surpassed no matter how
great A is because the decrease in F is exponential.

Returning to the example of -10A + 1 G = 9G
In space where G=0 (and true zero is beyond Pluto)
If G=0, then
-10A + 0G=1G
That is to say, no matter how big A is, G will never surpass 1

This is because what we are observing under 1 G is:
-10A(A(E squared)) + 1G = 9G

In space where G=0, E=A(G squared) or (E squared)=AG or G=A(E squared)

A(E squared)) on earth is 1, that is to say 1G
So -10A(A(E squared)) + 1G = 9G
Because
-10A(1) + 1G = 9G

When G=0
-10A + 0G=1G
Because the true equation is:
-10A(A(E squared)) + 0G=1G
Since E=A(G squared), there is an exponential decrease in F as A
increases.
A(E squared) will therefore not remain at the earth constant of 1, but
rather decrease exponentially towards 0

So in the example:
-10A(A(E squared)) + 0G=1G
A(E squared)=0.1
Therefore -10A(A(0.1) + 0G=1G
That is to say:
10A(0.1) + 0G=1G
Simplified to 1A+0G=1G
No matter how large A is, A(A(E squared)) + 0G=1G where G=0

This theory states that the artificial gravitational forces on the body
caused by massive acceleration in true zero gravities will never
surpass the natural gravity of earth and that this is caused by an
exponential decrease in F. Hence E=M(C squared) does not create a light
barrier where G=0. Rather F=MA holds true. The exponential decrease in
F theorised in E=A(G squared) cancels the exponential increase in M
theorised in E=M(C squared).

.

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