Re: Why does Capacitance decrease with "r" but F decreases with "r^2"?
- From: "Sue..." <suzysewnshow@xxxxxxxxxxxx>
- Date: 19 Jun 2006 13:14:58 -0700
Igor wrote:
Sue... wrote:
guskz@xxxxxxxxxxx wrote:
Wheter the capacitor's dielectric is space itself or another material,
why does Capacitance decrease with "r" but F decreases with "r^2"?
It would seem logical that if the attractive force between the charges
SUBSTANTIALLY decreases by r^2 then it doesn't seem logical that the
capacity to retain these charges(capacitance) in a capacitor decrease
only by r (even if space is the dielectric)?
F= kQq/r^2 (and capacitor's energy field: E = KQq/r^2) where as
Capacitance = Area/ (k * r)
<< These formulae are valid for any type of capacitor,
Wrong! Learn some basic electronics.
.
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