Re: Since k varies but not G suggests an Eather


Sue... wrote:
guskz@xxxxxxxxxxx wrote:

snip

So you're saying instead of applying the total charges in space to the
equation and using "k for space", they are varying "k" instead so as
to include the charges in the medium (as opposed to the charges outside
the medium)?

Whether charges exist ~outside the medium~ or not
does not concern us. If they are absent, their charge is
zero. If they are present, they exist in e+ e- pairs so
their value is zero.

Relativity is the word:

In a way nothing is zero nor potential and all is kinetic (always in
motion, never stops).

Paired charges are neutral and not, but without question the field
shrinks to it's smallest hypothetical value and the force will not be
neutral but at it's maximum

and if you apply energy to seperate the charges then the field is
bigger volume wise but it's force decreases.


(F_neutral = kQq/r^2 where r is the constant distance e and p remain
when neutral and Epotential = (F - F_neutral)*r^1)

--------------------------------------

Since nothing is neutral and only the field shrinks as Randy said the
residual force of dipole charges is 1/r^3 same as a magnetic force.....


If you have two dipole charges, does the residual remain at 1/r^3 or is
it more or is it less?

(meaning inside the field of two paired charges F at 1/r^2, outside
these dipoles the field F at 1/r^3....therefore in between TWO
individual dipoles (2 paired charges) F at 1/r^3 and outside these TWO
individual dipoles F at ?????


if F residual remains with Two dipoles above then perhaps these
determine the permittivity of space, since the velocity of EM waves is
affected by k_dielectric medium even if the dielectric medium's
charges are neutral, as well LOW (not high) frequency EM waves and
static charges are also affected force wise by k_dielectric (even if
the dielectric medium's charges are neutral)....therefore likewise even
if the total charges in space are neutral they may affect(determine)
the permittivity of space and the velocity of light?






Try to remember that on a grand scale, every positive charge is
canceling out a negative charge. It is not the same a summing
up the mass of all the atoms in the universe.

So the universe has a total charge of zero, but its mass
is non-zero.

Sue...
snip

.

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