Re: c = constant is still under discussion in this group


"Martin Hogbin" <goatREMOVETHIS123@xxxxxxxxxx> wrote in message
news:GdidnUTzu8C7nj7ZRVnyvw@xxxxxxxxx
|
| "Sorcerer" <Headmaster@xxxxxxxxxxxxxxxxxx> wrote in message
news:29Aog.490381$tc.340219@xxxxxxxxxxxxxxxxxxxxxxxxxxxx
| >
| > "Rudolf Drabek" <newsrudy@xxxxxx> wrote in message
| > news:1151516048.818174.99200@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
| > This matter is not solved in this group.
| > It may be that it is solved, but I don't know the source.
| > One link I've found but can't recover, was optical with interference.
| > The various techs to measure c are, except of Römer, TWLS.
| >
| > Oh, do come off it, Rudi. All it takes is an oscilloscope and a couple
| > of phototransistors, I've measured the speed of light myself.
| > c is a different matter.
|
| You could not even measure the speed of a train.

I've already told you how, dumbest ***. It is you that cannot calibrate
doppler radar, you that doesn't know what speed is. Speed is the magnitude
of velocity, and velocity is NOT from A to A divided t'A-tA, whatever
your stupid god says.

Derivation of the cuckoo transformations:
Velocity should be used since that has both direction and
magnitude and is a vector. Speed is a scalar.
Ref: http://mathworld.wolfram.com/VectorSpace.html

½[tau(0,0,0,t)+tau(0,0,0,t+x'/(c-v)+x'/(c+v))] = tau(x',0,0,t+x'/(c-v))

"Hence if x' be taken infinitessimally small:- " <<<
(attempt to differentiate at a discontinuity, dtau/dx', undefined inverted
velocity)
Ref: http://mathworld.wolfram.com/Discontinuity.html

½[1/(v-c) + 1/(v+c)] * dtau/dt = dtau/dx' + 1/(c-v) * dtau/dt
dtau/dx' + v/(c²-v²) * dtau/dt = 0
tau = a * ( t - (vx' / (c²-v²)))
Show a= 1
tau = (t-vx/c²) / sqrt(1-v²/c²)

Ref:
http://www.fourmilab.ch/etexts/einstein/specrel/www/

Einstein was incompetent as a mathematician, his disciples
are likewise incompetent. He was extremely good as a huckster.

As a consequence, there exist paradoxes.
tau = (t-vx/c²)/sqrt(1-v²/c²)
tau = (t-vy/c²)/sqrt(1-u²/c²)
tau = (t-vz/c²)/sqrt(1-w²/c²)
xi = (x-vt)/sqrt(1-v²/c²)
eta = (y-ut)/sqrt(1-u²/c²)
zeta= (z-wt)/sqrt(1-w²/c²)

If one is right they all are, if one is wrong they all are.
Newton would have made breakfast of Einstein on toast.

Space is isotropic, spacetime isn't. You need 3 time axes, not one.
Math is way over your stupid head, tho, Pigbin.

Androcles.



.