Re: derivation of kinetic energy
- From: "N:dlzc D:aol T:com \(dlzc\)" <N: dlzc1 D:cox T:net@xxxxxxxxxx>
- Date: Fri, 14 Jul 2006 18:22:02 -0700
Dear castertroy14:
<castertroy14@xxxxxxxxxxx> wrote in message
news:1152922791.949560.235820@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
can anyone show me the process of getting
equation (2) from equation (1).
(1) D(mv / (1-v^2/c^2)^0.5)
(2) m(1 - v^2/c^2)^-1.5 Dv
I don't see how that relates to kinetic energy.
http://hyperphysics.phy-astr.gsu.edu/hbase/relativ/relmom.html#c4
David A. Smith
.
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