Re: This is What Einstein Actually Did.

Henri Wilson wrote:
The BaTh can match just about any star curve.

Of course it can.
It is a curve drawing program where you can enter
a set parameters with no physical significance.

> How much more evidence do you
need. Have a look at 'contact binary' EF Dra:
http://www.users.bigpond.com/hewn/efdra.jpg.

If we assume the orbit to be roughly circular,
the BaT predicts the following variation in magnitude:

delta_m = 2.5*log((1 + 2*pi*d*v/(p*c^2))/(1 - 2*pi*d*v/(p*c^2)))
where:
d = distance [m]
v = amplitude of radial velocity [m/s]
p = period [s]

You can see the radial velocity of the components here:
http://tinyurl.com/jylt7

Note there are two components.

If we use your "distance" d = 0.07 LY,
each component will according to the ballistic theory
vary in intensity like this:

Component with smallest radial velocity : delta_m = 0.13
Component with biggest radial velocity : delta_m = 0.88

So which component is the WCH? :-)

It doesn't add up either way.

[..]


I gather it is a much broader form of extinction. It appears to be dependent on
the binary's period. I have discovered what seems to be a genuine relationship.
That must mean something. The unification distance (Du) for EF Dra is only
about 0.07 LY ..or 21 times the orbit period. For Algol, Du is around 30 LYs.

Of course your "unification distance" depends on the binary's period.
That is blatantly obvious from the equation above.
This "genuine relationship" should tell you the obvious:
Your "unification distance" has no physical significance whatsoever,
it is nothing but a parameter in your drawing program you have
to tune to make it generate the right light curve.
The smaller the p is, the smaller p must you choose.

Paul
.

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