Re: Hard SR questions?
- From: "N:dlzc D:aol T:com \(dlzc\)" <N: dlzc1 D:cox T:net@xxxxxxxxxx>
- Date: Sun, 13 Aug 2006 11:30:11 -0700
Dear jt64:
<jt64@xxxxxxxx> wrote in message
news:1155492275.314190.173840@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
N:dlzc D:aol T:com (dlzc) skrev:
Dear jt64:
<jt64@xxxxxxxx> wrote in message
news:1154870281.617016.89810@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Ship (A) travel 0.99c approaching earth.
Presumably earth = B?
Presumably the 0.99c is as determined by B?
gamma = ~7
let c = 300,000 km/sec
At a distance of 300 000 km as seen from
planet (B) inertial frame the ship start a
framed TV transmission.
... assumed the transmission is periodic, continuous, and the
last frame is completed as A passes B.
The transmission is such that 60 frames will
be sent from ship (A) during the distance of
300 000 km relative earths inertial frame.
Now my question.
... Question*s* ...
1. How long time will it take to travel to
planet using (ship point of view).
"It"? Do you mean the transmission or the ship? It is a
continuous data stream, whose last frame exits A's transmitter
just as A passes B, right?
The distance travelled during this transmission is (300,000 /
7)
km. The ship also measures B moving at 0.99c. So the
duration
is
1/7 = (1 + 0.99)*t
t = 0.07 sec.
2. What is the framerate for the transmission
within the ship.(ship point of view)
To meet your givens:
60 / 0.07 = 840 frames per second.
No that would be 420 fps, with perfect certainty, because as
you
remember...
Bull.
....
(*5*) How long was the time span between the
first and last frame(planet point of view)
From the *start* of the first frame...
0.01 seconds.
framerate: 60 / 0.01 = 6000 Hz
checking to see if we get ship's gamma:
6000 / 7 = 857 Hz ... the difference between this and 840 Hz
is
roundoff error.
Please note that 420 Hz is very far from 840 Hz, which
calculation you accepted without comment.
David A. Smith
.
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