Re: Hard SR questions?




N:dlzc D:aol T:com (dlzc) skrev:

Dear jt64:

<jt64@xxxxxxxx> wrote in message
news:1154870281.617016.89810@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Ship (A) travel 0.99c approaching earth.

Presumably earth = B?
Presumably the 0.99c is as determined by B?

gamma = ~7
let c = 300,000 km/sec

At a distance of 300 000 km as seen from
planet (B) inertial frame the ship start a
framed TV transmission.

... assumed the transmission is periodic, continuous, and the
last frame is completed as A passes B.

The transmission is such that 60 frames will
be sent from ship (A) during the distance of
300 000 km relative earths inertial frame.

Now my question.

... Question*s* ...

1. How long time will it take to travel to
planet using (ship point of view).

"It"? Do you mean the transmission or the ship? It is a
continuous data stream, whose last frame exits A's transmitter
just as A passes B, right?

The distance travelled during this transmission is (300,000 / 7)
km. The ship also measures B moving at 0.99c. So the duration
is

1/7 = (1 + 0.99)*t

No banana for you Smith the distance not 600 000 km you can not add
either time or length of two objects travelin one frame and say that is
the time or distance measured.

t = 0.07 sec.

2. What is the framerate for the transmission
within the ship.(ship point of view)

To meet your givens:
60 / 0.07 = 840 frames per second.

3. How long will it take until the front of first frame
is received at planet.(planet point of view)

How about the frame previous to the one that started emitting at
300,000? The math is cleaner. The one that just finished at
300,000 km arrived 1 second later.

4. How long will it take until the ship pass planet.
(planet point of view)

1 / 0.99 = 1.01 seconds

(*5*) How long was the time span between the
first and last frame(planet point of view)

From the *start* of the first frame...

0.01 seconds.
framerate: 60 / 0.01 = 6000 Hz
checking to see if we get ship's gamma:
6000 / 7 = 857 Hz ... the difference between this and 840 Hz is
roundoff error.

No one expects you to *like* relativity. But you will find that
it is self-consistent.

David A. Smith

.



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