Re: Analyse This!
- From: "me" <ililililil@xxxxxxxxxxxx>
- Date: 16 Aug 2006 12:14:28 -0700
Igor wrote:
me wrote:
Igor wrote:
standard deviation wrote:
Dirk Van de moortel wrote:
So his biggest blunder could well have been calling his
introduction of the constant his biggest blunder ;-)
Dirk Vdm
who tald yo that it shod be constatn?
that biggest blunder wol be that he called
it constant, which is not
Well, an additional term involving an arbitrary scalar function times
the metric tensor can be added to the Einstein equations and and still
you mean a factor, not a term,
you times factors not terms,
you add terms
No, I mean a term. Read it again.
i just did, yo are okay, i do appologise
what is scalar function, one taking
a scalar as input or returning a
scalar as output?
Yes.
which one of them is yes? both?
how do you times a scalar
function on a tensor, please explain
Same as scalar multiplication on a vectot. It's an outer product. All
rhe components of the tensor get multiplied.
isnt that ilegal?
a scalar times another scalar?
No.
scalars has no direction, nor dimension
Close, but I think that you might misunderstand what a scalar actually
is. It's an invariant number.
ok,but
a scalar is a rank 0 tensor
a vector is a rank 1 tensor
a matrice is a rank2 tensor
a cubic matrice is a rank 3 tensor, aka 3 dimensions etc
its ilegal ta multiply tensors with difrent ranks, thay
dont have the same domain of definition
is rank 0 an exception?
maintain their zero covariant divergence. The arbitrary scalar
function has no choice but to be constant for that to occur. These
conditions are not just arbitrarily assigned, they're derived.
do you mind a link with the derivations
Any GR textbook is a good place to start.
me reading books
i write books, i dont read books
.
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