Re: Analyse This!
- From: "Igor" <thoovler@xxxxxxxxxx>
- Date: 18 Aug 2006 10:11:38 -0700
me wrote:
Igor wrote:
me wrote:
Igor wrote:
me wrote:
Igor wrote:
standard deviation wrote:
Dirk Van de moortel wrote:
So his biggest blunder could well have been calling his
introduction of the constant his biggest blunder ;-)
Dirk Vdm
who tald yo that it shod be constatn?
that biggest blunder wol be that he called
it constant, which is not
Well, an additional term involving an arbitrary scalar function times
the metric tensor can be added to the Einstein equations and and still
you mean a factor, not a term,
you times factors not terms,
you add terms
No, I mean a term. Read it again.
i just did, yo are okay, i do appologise
what is scalar function, one taking
a scalar as input or returning a
scalar as output?
Yes.
which one of them is yes? both?
Yes to both.
how do you times a scalar
function on a tensor, please explain
Same as scalar multiplication on a vectot. It's an outer product. All
rhe components of the tensor get multiplied.
isnt that ilegal?
No. Sounds like you learn to learn some things about tensors.
a scalar times another scalar?
No.
scalars has no direction, nor dimension
Close, but I think that you might misunderstand what a scalar actually
is. It's an invariant number.
ok,but
a scalar is a rank 0 tensor
a vector is a rank 1 tensor
a matrice is a rank2 tensor
a cubic matrice is a rank 3 tensor, aka 3 dimensions etc
its ilegal ta multiply tensors with difrent ranks, thay
dont have the same domain of definition
Again, it's not. You can form a new tensor by multiplying two tensors
of different ranks. This is called an outer product. You end up with a
new tensor with rank equal to the sum of the ranks of the two tensors.
you make things more clear for me, but still
even tensors of same rank cant be multiplyed,
unless same domain defined
please explain
tensor A: rank 2, 2x2
tensor B: rank 2, 3x3
you cant multiply them like that, you pad A with zeros?
Have you ever heard of a tensor product, sometimes referred to as a
direct product? You'll find more info here:
http://en.wikipedia.org/wiki/Tensor_product
.
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