Re: Evidences for the ether

Sorcerer wrote:
"Paul B. Andersen" <paul.b.andersen@xxxxxxxxxxxxxxxx> wrote in message news:ec408q$m0s$1@xxxxxxxxxxxxxxxxxxx
| Sorcerer wrote:
| > "Paul B. Andersen" <paul.b.andersen@xxxxxxxxxxxxxxxx> wrote in message
| > news:ebvv8a$p7r$1@xxxxxxxxxxxxxxxxxxx
| > | Sorcerer wrote:
| > | > "Paul B. Andersen" <paul.b.andersen@xxxxxxxxxxxxxxxx> wrote: | > | > | I want to know how the receiver computes its position.
| > | >
| > | > I've told you, the details of the algorithm varies from manufacturer
| > | > to manufacturer. ANYONE can analyze data.
| > |
| > | Anyone but you?
| >
| > Even I.
| >
| > | I didn't ask for the details of the algorithm, I asked for
| > | the principle, which does not vary but is always the same.
| >
| > What is so difficult about triangulation? That IS the principle.
| >
| > Construct a sphere of radius vt where v is the signal velocity
| > around each satellite and where the three spheres intersect is
| > where the receiver is.
|
| OK. We are making progress. :-)

Now we are not. You asked if I know how it works and it is
BLATANTLY OBVIOUSLY do, you've said OK.

| The question is now - how is the t determined?

Use your brain... oops, you don't have one. Too bad, I'm
not interested in this kindergarten crap, you figure it out.

I'll give you a hint:
"But the ray moves relatively to the initial point of k, when measured in the stationary system, with the velocity c-v, so that

http://www.fourmilab.ch/etexts/einstein/specrel/www/figures/img31.gif

v is zero when the satellite is directly overhead (smallest sphere, least atmosphere

to penetrate at lower speed), so any height error is down to the clock being wrong.

GPS receivers regularly get altitude errors.

Military standard GPS receivers have damaged clocks built in that keep pace with the damaged clocks in the satellites, but that's a military secret I'm not supposed to tell you about :-)

See, when the US spots an incoming missile guided by GPS, all they have to do is change the satellite clock or stated position to steer the missile into the water, then change it back again.

It's a short hiatus in operations. One or two civilians then tap their receivers and either take it in for service or else shrug, shipping is too slow to be affected by it much and anyway everyone got by without it before any were launched.

The USA WANTS everyone to use GPS, then they have control.

That is really how GPS works, and they'll be happy to sell you a receiver, too.

You aren't so gullible you'd believe that crap they publish on the internet, surely?

Hmm... I really think you are.

Androcles.

Did you notice that I didn't interrupt your verbose lecture?
But now, when we are at the end, I will assume that I am
allowed to ask questions.

And the question I will ask is the one you seem to be quite
desperate to evade, and which you still haven't answered,
namely how the receiver calculates the time it takes for
the signal to go from the satellite to the receiver.

Your answer so far is:
"Use your brain... oops, you don't have one. Too bad, I'm
not interested in this kindergarten crap, you figure it out."

To sum it up:
1. We know the position of the satellite when the signal was sent.
2. We know the satellite clock time when the signal was sent.
3. We know the distance to the satellite is d = vt, where v is
the known signal speed, and t is the time it takes for
the signal to go from the satellite to the receiver.

The question you seem unable to answer is still:
How does the receiver determine the time t it takes for
the signal to go from the satellite to the receiver?

If you cannot answer this question, you don't know
how the GPS works. But this kindergarten stuff is
easy to answer, isn't it?
So why don't you?

Paul
.

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