FOOLSIH DONKEY sits in public after being beaten

rambus2...@xxxxxxxxx wrote:
physics.einstein@xxxxxxxxx wrote:
physics.einstein@xxxxxxxxx wrote:
rambus2005@xxxxxxxxx wrote:
physics.einstein@xxxxxxxxx wrote:
rambus2005@xxxxxxxxx wrote:
physics.einstein@xxxxxxxxx wrote:
rambus2005@xxxxxxxxx wrote:
physics.einstein@xxxxxxxxx wrote:
rambus2005@xxxxxxxxx wrote:
physics.einstein@xxxxxxxxx wrote:

mathematical equation
WRITE DOWN EQAUTION BASED UPON EINSTEIN'S SEP. 1905 PAPER about
Increase in Mass and momentum variation.


Hey imbecile,

Neither I nor Einstein wrote such an idiocy, you did! In your own
"paper"
=========AJAY SHARMA responds =========== to
Donkey rambus2...@xxxxxxxxx

Donkey,
I have asked you over 17 times to give
mathematical equation
WRITE DOWN EQAUTION BASED UPON EINSTEIN'S SEP. 1905 PAPER about
Increase in Mass and momentum variation.

You don't get it cretin,

Einstein never wrote that, you wrote this idiocy in your own paper. You
repeated it over 28 pages, moron.

===========AJAY SHARMA responds to Universal Donkey , RAMBUS
2005@xxxxxxxxx===========
Donkey rambus2...@xxxxxxxxx



Universal Donkey Rambus 2005.
You have written in previous posts that
'increase in 'mass of body' is due to 'momentum variations'
in Einstein's Sep 1905 paper.

Donkey dont be barking dog, but work ot keep silent.
Donkey , Simply write down the eqaution. It is your donkeyhood, that
you are NOT WRITING THE EQAUTION. When you try to write the eqaution
you will understand the limitations of Einstein's derivation.
I will finish the discussion.
Donkey, I am writing for all reader of world of science who are
reading this.

I have asked you over 17 times to give
mathematical equation
WRITE DOWN EQAUTION BASED UPON EINSTEIN'S SEP. 1905 PAPER about
Increase in Mass and momentum variation.

AJAY SHARMA

Cretin,

I have written that YOU are mistaking momentum variation for mass
increase. Not in Einstein paper, in YOUR piece of garbage.
Which makes your 28 pages of delirium tremens a piece of garbage.

=========AJAY SHARMA respond to Donkey
Rambus2005@xxxxxxxxx============

Donkey I allow you to change the stand you want.
Donkey , you have just written
"""I have written that YOU are mistaking momentum variation for mass
increase.""

Donkey let me know
(I) Where in my paper page no, section no, line no. equation no.
I am miataken about ' momentum variation' for 'increase in mass'



Cretin,

You don't know your own ***. You claim "mass increase" the first time
at equation (13) , section 1.3.1 in your *** paper.

===AJAY SHARMA responds to Donkey , rambus2005@xxxxxxxxx==========

Foolish donkey posing intelligent.

Donkey, This Time You Did Not Write “Momentum Variation” And
“Increase In Mass”
Which You Were Writing Over And Over Again.
Donkey , you have asked this in first post , but your aim was to defame
the work only.
Part I
Universal Donkey listen
Einstein derived equation L = Δ mc2 ( LIGHT ENERGY MASS inter
conversion equation) under classical conditions.

Einstein’s derivation is valid under many conditions e.g
(i) If body emits one light wave or two light waves or n light waves of
EQUAL or UNEQAUL ENERGY..
(ii) After emission of Light Energy the body MAY MOVE or REMAIN at
REST.
(iii) The light waves may be emitted at any angle.
(vi) The relative velocity v must remains in classical region.

Energy is emitted in every case mass decreases i.e. inter conversion of
mass-energy.

Einstein did calculations under the MOST SUITABLE CONDITIONS e.g.
(a) Body remains PERFECTLY AT REST after emission of light energy.
The result is L = Δ mc2,
(b) Einstein did not calculate, UNDER GENERAL CONDITIONS. The rest of
cases are completed
here and in some cases results are not correct.
This is the theme.

Part II

Einstein’s 27 Sep 1905 paper available at
http://www.fourmilab.ch/etexts/einstein/E_mc2/www/

Einstein has considered the variation of light energy which is give by
equation
l* = l{1 – v/c cos φ } /√[1 – v2 /c2]
(1)
This equation is from Einstein’s June 1905 paper. On eq..(1) whole
the derivation is based.
Thus in Einstein’s derivation even if body moves after emission of
light energy then ‘v’ will change in eq.(1).
Einstein’s derivation is limited to classical region of v only. Final
equation is independent of ‘v’

EINSTEIN HAS DONE ALL CALCULATIONS IN CLASSICAL REGION.

Using eq.(1) Einstein measured the magnitude of light energy .Then with
help of equation
Einstein related emission of light energy with decrease in mass.
The relevant equations in Einstein’s paper are UNNUMBERED EQAUTIONS
eq.(2-4) in Einstein’s paper.

I quote the equations
Eo = E1 + 0.5L +0.5L = E1 + L (2)
Ho = H1 + β L (4)
(Ho – Eo ) – (H1 – E1) = L [β –1] (5)

Donkey, Where Is Your Momentum Variation, You Were Shouting Since Very
First Post.

Part III
In case of eq.(13) after emission of light energy (at angle phi= 89
o) the body remains at rest or recoils with infinitesimally small
velocity and relative velocity v is in classical region. Thus
Einstein’s derivation is applicable, we can calculate in moving
frame, light energy with help of eq.(1), which is main equation.

Donkey, eq.(13) in my paper is absolutely correct. I quote from the
paper

Ho = H1 + β L( 1 – v/c cos89 o)
Ho = H1 + β L (1– 0.017452406 v/c)
Now proceeding as in Eq.(5) to Eq.(10) we get
Δ m = – 0.03490L/cv + L/c2 (13)
Thus when body emits light energy L in single wave making angle of 89 o
then it implies
that AS ENERGY IS EMITETD ITS MASS INCREASES.
So, DONKEY, everything is right.

Further see if angle is 90 i.e.
Ho = H1 + β L( 1 – v/c cos90 o)= H1 + β L
And we get
Δ m = L/c2 or L = Δ mc2
It is just to show that how mass depends upon angle.
So try to understand everything is in order.

AJAY SHARMA

Yes idiot, you are posting more of your cretinisms following the
ill-fated eq. 13 in section 1.3.1.
The more you post, the more obvious your idiocies.


===AJAY SHARMA responds to Donkey , rambus2005@xxxxxxxxx==========

Foolish donkey posing intelligent.

Donkey, This Time You Did Not Write “Momentum Variation” And
“Increase In Mass”
Which You Were Writing Over And Over Again.
Donkey , you have asked this in first post , but your aim was to defame
the work only.
Part I
Universal Donkey listen
Einstein derived equation L = Δ mc2 ( LIGHT ENERGY MASS inter
conversion equation)
under classical conditions.

Einstein’s derivation is valid under many conditions e.g
(i) If body emits one light wave or two light waves or n light waves of
EQUAL or UNEQAUL ENERGY..
(ii) After emission of Light Energy the body MAY MOVE or REMAIN at
REST.
(iii) The light waves may be emitted at any angle.
(vi) The relative velocity v must remains in classical region.

Energy is emitted in every case mass decreases i.e. inter conversion of
mass-energy.

Einstein did calculations under the MOST SUITABLE CONDITIONS e.g.
(a) Body remains PERFECTLY AT REST after emission of light energy.
The result is L = Δ mc2,
(b) Einstein did not calculate, UNDER GENERAL CONDITIONS. The rest of
cases are completed here and in some cases results are not correct.
This is the theme.

Part II

Einstein’s 27 Sep 1905 paper available at
http://www.fourmilab.ch/etexts/einstein/E_mc2/www/

Einstein has considered the variation of light energy which is give by
equation
l* = l{1 – v/c cos φ } /√[1 – v2 /c2] (1)
This equation is from Einstein’s June 1905 paper. On eq.(1) whole
the derivation is based.
Thus in Einstein’s derivation even if body moves after emission of
light energy then ‘v’ will change in eq.(1). Einstein’s
derivation is limited to classical region of v only. Final equation is
independent of ‘v’

EINSTEIN HAS DONE ALL CALCULATIONS IN CLASSICAL REGION.

Using eq.(1) Einstein measured the magnitude of light energy .Then with
help of equation Einstein related emission of light energy with
decrease in mass.
The relevant equations in Einstein’s paper are UNNUMBERED EQAUTIONS
eq.(2-4) in Einstein’s paper.

I quote the equations
Eo = E1 + 0.5L +0.5L = E1 + L (2)
Ho = H1 + β L (4)
(Ho – Eo ) – (H1 – E1) = L [β –1] (5)

Donkey, Where Is Your Momentum Variation, You Were Shouting Since Very
First Post.

Part III
In case of eq.(13) after emission of light energy (at angle phi= 89
o) the body remains at rest or recoils with infinitesimally small
velocity and relative velocity v is in classical region. Thus
Einstein’s derivation is applicable, we can calculate in moving
frame, light energy with help of eq.(1), which is main equation.

Donkey, eq.(13) in my paper is absolutely correct. I quote from the
paper

Ho = H1 + β L( 1 – v/c cos89 o)
Ho = H1 + β L (1– 0.017452406 v/c)
Now proceeding as in Eq.(5) to Eq.(10) we get
Δ m = – 0.03490L/cv + L/c2 (13)
Thus when body emits light energy L in single wave making angle of 89 o
then it implies
that AS ENERGY IS EMITETD ITS MASS INCREASES.
So, DONKEY, everything is right.

Further see if angle is 90 i.e.
Ho = H1 + β L( 1 – v/c cos90 o)= H1 + β L
And we get
Δ m = L/c2 or L = Δ mc2
It is just to show that how mass depends upon angle.
So try to understand everything is in order.

AJAY SHARMA



Ajay,


You are digging yourself deeper and deeper into the *** you have
created starting at eq. 13 in section 1.3.1 of your *** paper.

=========AJAY SHARMA responds to DONKEY rambus=========
FOOLISH DONKEY RAMBUS2005@xxxxxxxxx ,

You proved the name given to you DONKEY.
Everything is correct in paper.
Justify your claims.

DONKEY I KNEW YOU CAN NOT DO ANYTHING EXCEPT BARKING.
SHAME ON YOU DONKEY

AJAY SHARMA

.

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