Re: The Twin Paradox explained from the moving twin ?


"Nicolaas Vroom" <nicolaas.vroom@xxxxxxxxxx> wrote in message
news:oJ9Og.75563$t31.1106993@xxxxxxxxxxxxxxxxxxxxxxxx
Question:
Is it possible to explain the Twin Experiment from the moving point of
view ?

IMO this is not possible.

When the two Observers meet they realize that there clocks are not the
same.
To be more specific: The clock of the moving observer runs behind.
The clock of the moving observer runs slow.

All observers have to agree that the *average* clock rate (in ticks per
whatever inertial reference second) was less than the inertial clock rate
while the clocks were separated .

To explain the Observer at rest will say:
Look on my clock I read 10000 counts.
Based on the speed v (Lorentz Transformation) gamma is 0.5
That means your clock should read 5000 counts.
Which is what we measure. qed.

The question is: Is it possible to explain this also from the
point of view of moving observer ?

IMO this it not possible.
The moving Observer has to accept what the Observer at rest tells him.

The moving observer makes the same comparison as the one "at rest", and
reaches the same conclusion.

For more details goto : http://users.telenet.be/nicvroom/dirk3.htm

At that url there is also a sketch which explains this from the
moving point of view.
But that sketch is wrong so it seems.

The url shows that before the point of return
both observers will observe the same.
The "trick" is that the moving observer does not stay
at rest in his original frame.

Of course - and anyone can choose whatever inertial frame he wants as
reference frame.

Harald

Nicolaas Vroom.

http://users.telenet.be/nicvroom/




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