Re: The Twin Paradox explained from the moving twin ?




"The Ghost In The Machine" <ewill@xxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:har0u3-lkm.ln1@xxxxxxxxxxxxxxxxxxxxxxxxxx
| In sci.physics.relativity, Sorcerer
| <Headmaster@xxxxxxxxxxxxxxxxxx>
| wrote
| on Sun, 17 Sep 2006 18:41:38 GMT
| <CFgPg.5510$2Q4.2286@xxxxxxxxxxxxxxxxxxxxxxxxx>:
| >
| > "The Ghost In The Machine" <ewill@xxxxxxxxxxxxxxxxxxxxxxx> wrote in
message
| > news:c8d0u3-cjl.ln1@xxxxxxxxxxxxxxxxxxxxxxxxxx
| > | In sci.physics.relativity, G. L. Bradford
| > | <glbrad01@xxxxxxxxxxxxx>
| > | wrote
| > | on Sun, 17 Sep 2006 08:05:06 -0400
| > | <HM-dndgFQdDTp5DYnZ2dnUVZ_u2dnZ2d@xxxxxxxxxxxxx>:
| > | > (Sigh)
| > | >
| > | > A traveler is traveling between two stars measured at each end to
be
| > ten
| > | > light years apart. Any observer on an Earth type planet at star A
will
| > | > observe star B to be zero minus ten years relative to his own atomic
| > clock
| > | > time, thus ten light years distant from him. Any observer on an
Earth
| > type
| > | > planet at star B will observe star A to be zero minus ten years
relative
| > to
| > | > his own atomic clock time, thus ten light years distant from him.
| > | >
| > | > The traveler stands beside the observer on the planet at star A
and
| > | > observes with him star B. They both observe star B to be ten light
years
| > | > away or zero minus ten years in time relative to star A. The
traveler
| > boards
| > | > his space supership and takes off for star B.
| > | >
| > | > It takes the traveler two years to get one light year from star A.
| > Star A,
| > |
| > | [snip rest of very long-winded diatribe for brevity by the Ghost In
| > | The Machine]
| > |
| > | I'm assuming this means v = 0.5 c; this gives a transit time of
| > | about 40 years objective but only 34.64 subjective,
| >
| > Not for tachyon that does 27 km in 1/11245 seconds.
|
| OK, lemme put it to you this way.
|
| A proton's mass is 1.673 * 10^-27 kg.

*** that ***, I wanna see the tachyon you promised, dad.
Are we there yet?
Are we there yet?
Are we there yet?
Are we there yet?

| The circumference is 27 km, give or take.


Yeah yeah... I wanna see the tachyon, dad.


Therefore, the frequency --
| 1 over the lap time, if you will -- should be about 0.735 MHz.

Where did you learn hard sums?
lap time 8.8928412627834593152512227656736e-5 seconds for
a lap of 27km = 303,615,000 m/s average Geschwindigkeit.
Are we there yet?
Are we there yet?

| But it's not specified at 0.735 MHz. Why is that?

*** that ***, I wanna see the tachyon, dad.
Are we there yet?
Are we there yet?
Are we there yet?
Are we there yet?
Are we there yet?
Are we there yet?
Are we there yet?
Are we there yet?
Androcles.



.


Quantcast