Re: Lorentz transformations when the velocity is not along the x-axis.

In sci.physics.relativity, Golden Boar
<goldenboar@xxxxxxxxxxx>
wrote
on 10 Oct 2006 05:15:21 -0700
<1160482521.106324.184610@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>:

The Ghost In The Machine wrote:
In sci.physics.relativity, Golden Boar
<goldenboar@xxxxxxxxxxx>
wrote
on 9 Oct 2006 09:54:10 -0700
<1160412850.612902.115720@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>:

Dirk Van de moortel wrote:

"Golden Boar" <goldenboar@xxxxxxxxxxx> wrote in message news:1160336946.327036.21480@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

Dirk Van de moortel wrote:
"Golden Boar" <goldenboar@xxxxxxxxxxx> wrote in message news:1160335412.356098.274110@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

Dirk Van de moortel wrote:
"Golden Boar" <goldenboar@xxxxxxxxxxx> wrote in message news:1160332972.392082.286490@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

Dirk Van de moortel wrote:
"Golden Boar" <goldenboar@xxxxxxxxxxx> wrote in message news:1160330418.081744.116500@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

Dirk Van de moortel wrote:
"Golden Boar" <goldenboar@xxxxxxxxxxx> wrote in message news:1160328122.196687.156710@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

Dirk Van de moortel wrote:
"Golden Boar" <goldenboar@xxxxxxxxxxx> wrote in message news:1160325324.597342.185980@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

Dirk Van de moortel wrote:

[snip]

The answer is - and will remain - right here:
http://users.telenet.be/vdmoortel/dirk/Physics/Fumbles/GuestAppearance.html

Did you have a look at it?

Dirk Vdm

Yes, I have looked at it, and it does not answer the question.

I only had a hit from Androcles' IP-address.
Can you explain that?

Dirk Vdm

Quite easily.
You are simply mistaken.
I have a visied your site a couple of times today, and have just
visited it agian at 18:16 GMT.
So either your websites logging system is crap or you don't know that
much about networking. I'm betting on the latter.

No, I have another explanation.
Either you haven't visited it which means you are a liar,
or you are Androcles, which means you are a liar.
Caught with your pants down.


You still can't answer the question though can you?

You can't figure out the answer from the explanation that
you didn't even look at.

Quite hilraious.

Hilariously pitiful, indeed, imbecile.

Dirk Vdm

I have visited the site and I am not Androcles.

If your logs do not show a hit for 18:16 GMT, then your websites
logging system is crap.

If it does show a hit for that time, then post the IP address you are
referring to, and I will show you that you don't know what you're
talking about.

You have repeatedly avoided answering the simple question, because you
know that the answer will show that I have benn right all along.

You are an imbecile for not understanding or even trying
to understand the spoonfed information you received, and
for being caught in the act of lying, and there is nothing you
can do about it :-)

Dirk Vdm

I asked you to provide the IP address and I would prove this.
You did not provide the IP address, why was that?

Here are some clues.
Both of are ISP's are Telewest.
I am posting from Liverpool
Androcles is posting from Gillingham.

I have visited your website and I am not Androcles.
You are a blatant lier and a fool.

You haven't visited the site, little liar ;-)

I have visited the site, so it is you who is lying.
Provide the IP address that I asked for.



And you still havn't answered the simple question.

Look at the site. The answer is there.
It's not my fault that you are too much of a coward to look
at it and too stupid to understand it ;-)

I dont see a set of 3 equations,

That is because you are an imbecile and proud of it as well.

Dirk Vdm

Nope, it's because you havn't provided the set of equations which I am
asking you for.

vx = ?
vy = ?
vz = ?

Androclone, you are an imbecile.
Here is the answer:
http://users.telenet.be/vdmoortel/dirk/Physics/Fumbles/GuestAppearance.html
Paradoxically, I truly sincerely hope you'll never understand it ;-)

Dirk Vdm

If you think that answers the question, then you do not understand the
question.

I will restate the question. Given that c=1, v=0.9, t=5, x=9, y=6, and
z=3, what are the values of vx, vy and vz?


OK, I'm obviously missing something here. Is (x,y,z) the direction of
the v vector (with v being the magnitude) or just an arbitrary point in
3 space in one of the coordinate systems?

x,y,z is an arbitrary point, but in the specific case I have been
discussing, that point was also the origin of the primed frame.

Then the Lorentz can't apply. The two points (0,0,0,0)_K and
(0,0,0,0)_K' have to be physically coincident in order for the
standard Lorentz to apply, though one can multiply by a translation
tensor in a pinch.



AFAICT, the proper way to do this would be to specify the following.

[1] v, nx, ny, nz, where (nx^2+ny^2+nz^2) = 1. In other words, v is
the magnitude, n the normalized direction. In a pinch one can
use e.g. nx = x / sqrt(x^2+y^2+z^2).

That's all I wanted to hear, nx = x / sqrt(x^2 + y^2 + z^2).

Yes, except that the vector is not pointed at the point (x,y,z). I'm
frankly not sure *what* it's pointed at.

[rest snipped]

--
#191, ewill3@xxxxxxxxxxxxx
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