Re: THE GENERAL RELATIVITY.

Koobee Wublee wrote:
Paul B. Andersen wrote:
Look. Let us repeat what you have stated is correct.

This is the equation for the Doppler shift of a signal
emitted from a source in S, and observed by an observer in S'.

f' = f*(1 - (v/c)*cos(phi))/sqrt(1 - v^2/c^2)

That is, when p and v are transverse in the source frame S,
then phi = pi/2 and the equation above yields:
f' = f/sqrt(1 - v^2/c^2)

But if v and p are transverse in the observer frame S',
then phi' = pi/2 and cos(phi) = v/c

You should write p' instead of p to indicate the momentum of the
photon as observed by S'.

Sure.
But the important point is that the equation:
f' = f*(1 - (v/c)*cos(phi))/sqrt(1 - v^2/c^2)
is correct!

Paul B. Andersen wrote;
| If phi' = pi/2, phi = arccos(v/c)
|
| So we can conclude that if v and p are transverse in S',
| they are NOT transverse in S, because the angle between
| v and p is arccos(v/c) in S.
|
| You claimed this to be wrong.

Koobee Wublee responded:
| I actually don't see you are wrong here.

That is because it is correct!
So get this into your head, and don't repeat that
it is wrong in every second posting!

The issue is not the above.
>
Read carefully:
| If v and p are transverse in the observer frame S',
| they are NOT transverse in the source frame S,
| because the angle between v and p is arccos(v/c) in S.

And when cos(phi) = v/c, the Doppler equation:
f' = f*(1 - (v/c)*cos(phi))/sqrt(1 - v^2/c^2)

The equation above is wrong. It should be

Say - are you drunk, or what?
This is still the equation for the Doppler shift of a signal
emitted from a source in S, and observed by an observer in S':

f' = f*(1 - (v/c)*cos(phi))/sqrt(1 - v^2/c^2)

It is as correct now as it was above,
so what the hell are you talking about?


f = f' (1 - v cos(phi') / c) / sqrt(1 - v^2 / c^2)

yields:
f' = f*sqrt(1 - v^2/c^2)
which is a red shift

Wrong here. The observed frequency by S in this case should be
>
> f = f' / sqrt(1 - v^2 / c^2)
>
> Which is always a blue shift.

Sober up, man.
From whence did you get the idea that the observer is in S?
The observer is still in S', we never changed that.
---------------------------

Can't you read?
I even said:
Read carefully:
| If v and p are transverse in the observer frame S',..
##################

Why the hell don't you read what I write and respond to that
in stead of responding to something I never wrote?

Read the following again - carefully.
Please point out exactly what is wrong in _what I have written_!

Read carefully:
===============

This is the equation for the Doppler shift of a signal
emitted from a source in S, and observed by an observer in S':
-------------------------------------------------------------
f' = f*(1 - (v/c)*cos(phi))/sqrt(1 - v^2/c^2)

That is, when p and v are transverse in the source frame S,
then phi = pi/2 and the equation above yields:
f' = f/sqrt(1 - v^2/c^2)
That is, the observer in S' will observe a blue shift.
-----------------

But if v and p' are transverse in the observer frame S',
then phi' = pi/2 and cos(phi) = v/c
and the Doppler equation:
f' = f*(1 - (v/c)*cos(phi))/sqrt(1 - v^2/c^2)
yields:
f' = f*sqrt(1 - v^2/c^2)
That is, the observer in S' will observe a red shift.
------------------

You cannot make this wrong by pointing out that something
else is wrong!

Paul


.

Relevant Pages

  • Re: THE GENERAL RELATIVITY.
    ... That is, when p and v are transverse in the source frame S, ... But if v and p are transverse in the observer frame S', ... This is again a blue shift. ... This is still the equation for the Doppler shift of a signal ...
    (sci.physics.relativity)
  • Re: THE GENERAL RELATIVITY.
    ... So we can conclude that if v and p are transverse in S, ... which is a blue shift. ... So if the source is stationary in S and the observer in S', ...
    (sci.physics.relativity)
  • Re: THE GENERAL RELATIVITY.
    ... So we can conclude that if v and p are transverse in S, ... which is a blue shift. ... So if the source is stationary in S and the observer in S', ...
    (sci.physics.relativity)
  • Re: THE GENERAL RELATIVITY.
    ... So we can conclude that if v and p are transverse in S, ... which is a blue shift. ... If v and p are transverse in the observer frame S' ...
    (sci.physics.relativity)
  • Re: THE GENERAL RELATIVITY.
    ... So we can conclude that if v and p are transverse in S, ... which is a blue shift. ... If v and p are transverse in the observer frame S' ...
    (sci.physics.relativity)
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