Re: Special Relativity is Dead! (second proof)
- From: jan.verheul@xxxxxxxxxx
- Date: 19 Nov 2006 06:16:49 -0800
Dirk Van de moortel schreef:
I repeat:
Which formula do you use for this Doppler effect?
Can you show the calculation in detail?
Dirk Vdm
If I am doing calculations I always ignore what cancels out. That's
what you also do when multiplying fractions. Common factors cancel out.
You ignore them and "scratch them out". I did not use any formula for
Doppler effect in my calculations because it's useless. It cancels out
in the final situation as the traveling clock has returned home.
But if you want to check if I am capable of appreciating formulas, here
you go. I don't remember the formula for Doppler effect, so I will
derive them at the spot. I will express the observed frequency in terms
of the source frequency, the velocity of the observer, and the velocity
of the signal (ignoring relativistic effects for the moment).
If the velocity of the observer equals the velocity of the signal, the
observed frequency is zero. If the velocity of the observer is half the
frequency of the signal, the observed frequency is half the frequency
of the source. If the velocity of the observer is minus the velocity of
the signal, the observed frequency is twice the frequency of the
source. The formula should therefore be:
Fobserved = Fsource * (Vsignal - Vobserver) / Vsignal.
Satisfied?
The formula can also be expressed in terms of wavelengths. I will be
able to derive that formula as well.
NOTICE that the formula assumes the source is stationary!!! If you have
a moving source, you will get a different formula, with a factor in the
numerator that can become zero if source velocity approaches signal
velocity (with an infinitely high frequency in the limit).
My experiment has a stationary time pulse source, so the above formula
should work. Again, no formula is required as Doppler effects cancel
out in this experiment.
Regards, Jan.
.
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