Re: Special Relativity is Dead! (second proof)
- From: jan.verheul@xxxxxxxxxx
- Date: 19 Nov 2006 04:21:55 -0800
Dirk Van de moortel schreef:
In S.R. the calculation can be made from the viewpoint of K'
as well, but it is much more difficult, since K' is not an inertial
frame.
Since K' is not inertial, we don't have to calculate an integral
like
int{ sqrt( 1 - [v(t)/c]^2 ) dt }
where v(t) is the velocity of clock K' at time t according to
clock K, but this time we have to calculate something like
int{ sqrt( 1 - [v(t')/c]^2 ) ( 1+a x'(t') ) dt' }
where x'(t') and v'(t') are the distance and velocity of clock K
at time t' as seen by clock K'.
Needless to say this is a bit tricky, and *maybe* later I'll show
you how it can be done.
As long a you have not shown this, I'll stick with my conclusion that
S.R. is invalid. I don't see why this calculation should be "tricky".
I'm quite sure that it is "tricky" because it is concocted and not
based on the underlying principles of SR, namely that the speed of
light is the same for all observers under all circumstances.
But first let's get back to your statement about "the problem.
with this calculation".
When you want to calculate the number of times some kid's
jo-jo goes up and down on a merry-go-round on one of
Saturn's satelites, you need the equation of motion of the jo-jo,
and calculate an integral. When I give you these equations in
the kid's reference frame, this is rather simple.
Are you going to say that the problem with this calculation is
that it has not been made from the viewpoint of yourself, riding
a rollercoaster in Amsterdam? Are you going to insist that
someone goes through the trouble of finding the equations of
motion of the jo-jo in your frame, and verify whether the rather
difficult integral will produce the same number? If the person
is not prepared to do that for you, will you do the job yourself?
Dirk Vdm
A journey in one straight line to a far destination, and back again, is
infinitely more simple than a viewing the jojo from someone in a
merry-go-around on one of the moons of Saturn, seen from a
rollercoaster in Amsterdam...
The point is that quantities in general (and time delation in
particular) can be calculated in different ways. All ways should lead
to the same answer. If I want to know the number of squares in a grid,
I can count the number of rows and multiply it by the length of the
rows. I can also count the number of columns and multiply it by the
height of the columns. If both answers do not coincide, I do not
understand what I am counting and calculating. The same is true for
calculating time delation in twin experiments. If there is no obvious,
plain, straightforward way to calculate the time delation from the
viewpoint of the traveling clock... Forget about the theory. The theory
is not confirmed by the fact that every approach leads unequivocally to
the same result.
Regards, Jan.
.
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