Re: symmetric twins paradox
- From: "Paul B. Andersen" <paul.b.andersen@xxxxxxxxxxxxxxxx>
- Date: Tue, 21 Nov 2006 22:45:00 +0100
lkoluk2003@xxxxxxxxx wrote:
Hi,
I am not a physics, just an amateur. However, I treat myself as a
logician, so the paradoxes are in my interest. After I read the
discussions about the special relativity(SR) and twin's paradox,
believe that it can not be resolved within SR. The defenders of SR
claims that there is an asymmetry in the conditions of the twins and so
there is no paradox. However, one can easily think of an experiment in
which the twins are in symmetric conditions.
Let A B are the twins and C is a third observer. The twins move away
from the earth in opposite directions and C remains rest on the earth.
Assume their clock is synchronized just before the movement. After
accelaration twins continue to their journey in a constant speed. After
some time they return back and land on the earth. Let from the C's
point of view, the twins all accelarate at the same time and with the
same amount. The only difference between the twins is that they travel
in opposite directions. After returning back they compare their
clocks. If SR is true, according to C, the twins clock will slow down
with the same amount and their clocks must be the same. On the other
hand, according to the twin A, twin B's clock must be slow down and not
the same with his/her clock. The same thing is true for twin B. Of
course there can be only one result. However, according to SR, three
observer comes out with three different results.
How did you arrive at this conclusion?
Show your calculations, please.
The LT should be simple for one who prides himself of being
a logician.
Paul
.
For just objections relating to accelarations: the accelaration times
of the twins can be made arbitrararily smaller according to the
duration in which the twins travel at a constant speed, so their
affects can be vanished without a significant error.
Lokman Kolukisa
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