Re: symmetric twins paradox

Dear Sue:

Sue... wrote:
N:dlzc D:aol T:com (dlzc) wrote:
Dear lkoluk2003:

<lkoluk2003@xxxxxxxxx> wrote in message
news:1164106119.311251.148050@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
...
Let A B are the twins and C is a third observer. The twins
move away from the earth in opposite directions and C
remains rest on the earth. Assume their clock is
synchronized just before the movement. After
accelaration twins continue to their journey in a constant
speed. After some time they return back and land on the
earth. Let from the C's point of view, the twins all
accelarate at the same time and with the same amount.
The only difference between the twins is that they travel
in opposite directions. After returning back they
compare their clocks. If SR is true,

"true" is not part of science. "what is observed, within our
ability to measure" is part of science.

according to C, the twins clock will slow down with the
same amount and their clocks must be the same. On
the other hand, according to the twin A, twin B's clock
must be slow down and not the same with his/her
clock. The same thing is true for twin B. Of course
there can be only one result. However, according to
SR, three observer comes out with three different
results.

If you did the math, observer A sees observer B's clock
go very slowly on A's outbound, continue slowly for some
time with A inbound (since B's start-of-return doesn't reach
A until later) then sees B's clock rate increase until it
meets A at Earth, with net 0 difference at Earth.

So three observers in a symmetric situation yields two
results, because only two unique paths are described.

It is the words that trick your common sense, not the facts.
Use the math.

In response to your complaints about the elastic properties
of today's garden hose material and the possibility of
"bead bunching", we are proud to announce the all new and
improved

Three clocks, two different elapsed times. Argument? Beads, hoses?
I'm not looking to buy Manhattan...

David A. Smith

.

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