Re: relativity vs velocity addition
- From: "Sorcerer" <Headmaster@xxxxxxxxxxxxxxxxxx>
- Date: Tue, 12 Dec 2006 11:48:57 GMT
<lkoluk2003@xxxxxxxxx> wrote in message news:1165919683.448586.288430@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
| It seems that the assumption that the maximum distances between the
| twins during inbound and outbound part are equal is not generally true.
| I.e. the most general formula is t1=x1/v1 and t2=x2/v2 where x1 is not
| equal to x2. In this case, the only explanation is that the clock rates
| of both twins are the same even from the point of view of the twins.
|
| On the other hand, the relativity principle is fully compatible with
| this. I copied the following from my text in another threat.
| "Each tick in a clock is an event and an event's observed time can be
| different from time dilation. For example one can set a clock by using
| a light pulse
| and two mirrors.
The second is the duration of 9 192 631 770 periods of the radiation corresponding to the transition between the two hyperfine levels of the ground state of the cesium 133 atom.
http://physics.nist.gov/cuu/Units/second.html
See anything about setting a counter with two mirrors?
Send a caesium atom to Proxima Centauri and back, COUNTING transitions.
The count will match an identical caesium atom that remains here.
During the journey it will *appear* not to match due to
transitions being "in flight", aka Doppler shift.
There are no missing or additional counts, hence no count dilation,
hence no time dilation.
Einstein was an idiot.
The pulse is reflected between the mirrors and the
| time interval between the reflection times of mirror 1 can be
| considered as one tick of this clock. If the light speed is source
| dependent then the duration of each tick is the same regardless of the
| speed of the clock and the time delation."
|
| Assume there is a platform with the clock mentioned above and two
| observers A&B. The tick time of this clock would be t=2.x/c where x is
| the distance between the mirrors.
|
| Now let the platform carrying the observer B is moving with a constant
| speed v with respect to the observer A. The clock is placed in such a
| way that the light pulse movement is in the same direction with the
| platform's speed. Assume there is a time dilation B. I.e. t'=t.B where
| t' is the time measured by observer B and t is the time measured by the
| observer A. Since according to the observer B, there is nothing
| changed, so (s)he will observe the tick time as t'=2x'/c or 2.x'=c.t'.
|
| The relativity principle requires that the light speed is source
| dependent. Let this relative speed is k(v). Then the tick time for
| observer A would be
| t=2.x'/k(v) = c.t'/k(v ) = c.t.B/k(v)
|
| >From here we deduce k(v)=B.c. On the other hand x'/t'=x/t must be true.
| I.e. x'=x.B. So from here
|
| t=2.x'/k(v) = 2.x.B/(c.B) = 2.x/c
|
| same with if the speed was zero. As seen the observed tick time is
| independent from the speed and from the dilation factor. The same thing
| is true for any event including the movement of someting or at least
| any event whose time is measured by distance/speed. This is a perfect
| result because the twin paradox is fully resolved now(assuming the time
| measure always involves something which has a movement) and the
| dilation factor can be choosen without considering it.
|
| Best regards,
| Lokman Kolukisa
|
.
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